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What is 3y 18?
The numbers 3y times 18 equals 54. This is taught in math.
What is the y-intercept of the line given by the equation y 5x - 21?
-16
How do you Solve the system of equations using the substitution method Enter the answer as an ordered pair x - 3y equals -23 5x plus 6y equals 74?
From Equation 1: x = 3y - 23Substitute for x in equation 2: 5(3y - 23) + 6y = 74ie 15y - 115 + 6y = 74ie 21y - 115 = 74Add 115 to each side: 21y = 189Divide each side by 21: y = 9x = 3y - 23 ie 27 - 23 ie 4x = 4, y = 9
What is the ordered pair for 2x plus 5y equals 16 plus -5x minus 2y equals 2?
2x + 5y = 16 + (-5x) - 2y = 2 That gives 2x + 5y = 2 . . . . . . . . . . (I) and -5x - 2y = - 14 or 5x + 2y = 14 . . . . (II) (I)*5: 10x + 25y = 10 (II)*2: 10x + 4y = 28 Subtracting the second from the first, 21y = -18 so y = -18/21 = -6/7 and then by (I) x = 1 - 5y/2 = 1 - 5/2*(-6/7) = 1 + 15/7 = 22/7 So the ordered pair is (22/7, -6/7)
How do you solve these equations by substitution 2x-5y plus 2z equals 16 3x plus 2y-3z equals -19 4x-3y plus 4z equals 18?
If you mean: 2x-5y+2z = 16 and 3x+2y-3z = -19 and 4x-3y+4z = 18 then the solutions are found as follows:- 3(2x-5y+2z = 16) => 6x-15y+6z = 48 2(3x+2y-3z = -19) => 6x+4y-6z = -38 Adding the above: 12x-11y = 10 thus eliminating z 4(3x+2y-3z = -19) => 12x+8y-12z = -76 3(4x-3y+4z = 18) => 12x-9y+12z = 54 Adding the above: 24x-y = -22 thus eliminating z 2(12x-11y = 10) => 24x-22y = 20 1(24x-y = -22) => 24x-y = -22 Subtracting the above: -21y = 42 thus eliminating x If: -21y = 42 then y = -2 So by substitution: x = -1, y = -2 and z = 4 Check: (2*-1)-(5*-2)+(2*4) = 16 Check: (3*-1)+(2*-2)-(3*4) = -19 Check: (4*-1)-(3*-2)+(4*4) = 18
