The numbers 3y times 18 equals 54. This is taught in math.
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From Equation 1: x = 3y - 23Substitute for x in equation 2: 5(3y - 23) + 6y = 74ie 15y - 115 + 6y = 74ie 21y - 115 = 74Add 115 to each side: 21y = 189Divide each side by 21: y = 9x = 3y - 23 ie 27 - 23 ie 4x = 4, y = 9
2x + 5y = 16 + (-5x) - 2y = 2 That gives 2x + 5y = 2 . . . . . . . . . . (I) and -5x - 2y = - 14 or 5x + 2y = 14 . . . . (II) (I)*5: 10x + 25y = 10 (II)*2: 10x + 4y = 28 Subtracting the second from the first, 21y = -18 so y = -18/21 = -6/7 and then by (I) x = 1 - 5y/2 = 1 - 5/2*(-6/7) = 1 + 15/7 = 22/7 So the ordered pair is (22/7, -6/7)
If you mean: 2x-5y+2z = 16 and 3x+2y-3z = -19 and 4x-3y+4z = 18 then the solutions are found as follows:- 3(2x-5y+2z = 16) => 6x-15y+6z = 48 2(3x+2y-3z = -19) => 6x+4y-6z = -38 Adding the above: 12x-11y = 10 thus eliminating z 4(3x+2y-3z = -19) => 12x+8y-12z = -76 3(4x-3y+4z = 18) => 12x-9y+12z = 54 Adding the above: 24x-y = -22 thus eliminating z 2(12x-11y = 10) => 24x-22y = 20 1(24x-y = -22) => 24x-y = -22 Subtracting the above: -21y = 42 thus eliminating x If: -21y = 42 then y = -2 So by substitution: x = -1, y = -2 and z = 4 Check: (2*-1)-(5*-2)+(2*4) = 16 Check: (3*-1)+(2*-2)-(3*4) = -19 Check: (4*-1)-(3*-2)+(4*4) = 18
Terms of algebra
x-intercept = -21y-intercept = 168
Equations: 7x+4y = 9 and 2x+3y = 1 Multiply all terms in the 1st equation by 2 and all terms in the 2nd equation by 7 So: 14x+8y = 18 and 14x+21y = 7 Subtract the 1st equation from the 2nd equation: 13y = -11 => y = -11/13 By substituting y = -11/13 into any of the equations x = 23/13 Therefore the solutions are: x = 23/13 and y = -11/13
(2x - 3y)(2x - 7y)
3(2y + 3)(y + 2)
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It is an algebraic expression which cannot be evaluated without information about y.
From Equation 1: x = 3y - 23Substitute for x in equation 2: 5(3y - 23) + 6y = 74ie 15y - 115 + 6y = 74ie 21y - 115 = 74Add 115 to each side: 21y = 189Divide each side by 21: y = 9x = 3y - 23 ie 27 - 23 ie 4x = 4, y = 9
21
From first equation: x = 39 - 7ySubstitute this in second equation: 3(39 - 7y) - 2y = 2ie 117 - 21y - 2y = 2ie 115 = 23yie y = 5, making x = 4.
21
Eqn (A): => 2x + 5y = 16 Eqn (B): => 5x + 2y = -2 5*Eqn (A) - 2*Eqn (B): 21y = 84 => y = 4 Substituting for y in Eqn (a): x = -2