No, there are an infinite number of integers. So, there would be an infinite (infinity/2-1) number of positive integers. And, there would be an infinite (infinity-10) number of integers greater than ten.
1 2 3 4 5 6 7 8 9 10 11 12 13 14
10, 8, 6, 4, 2, 0 and all the negative even integers.
integers are x and x + 2, so x + 2 = 2x - 10 ie x = 12. Integers are 12 and 14
10-11-12
The positive integers less than 11 are the natural numbers 1-10.That is to say 1,2,3,4,5,6,7,8,9 and 10.
Assuming you refer to positive integers, the answer is 10:9
10*9*8=720
10
When one of the factors is less than or equal to 1, and the other is positive. Examples: 1 x 9 = 9 0 x 5 = 0 -1 x 10 = -10 If both are negative, it doesn't work: -10 x -10 = +100
2. That is the only one. And the 11 divisors are 2k where k = 0, 1, ,2, ... , 10
2 4 6 8 10 12 14 16 18 20 22 24
Assuming the two numbers are positive integers, the two numbers must be 10 and 7: 10 + 7 = 17 10 - 7 = 3
Take any negative integers, say -5 and -10, their sum is -15 which is smaller than both of them. We could have used 0 as well, so I should have said any non-positive integers. To see that is does not work with positive integers, take 5 and 10 whose sum is 15 which is BIGGER than either one.
The greatest positive even integer less than 12 is 10
No, there are an infinite number of integers. So, there would be an infinite (infinity/2-1) number of positive integers. And, there would be an infinite (infinity-10) number of integers greater than ten.
10, 12, 14, 16