In the key of C major, 2-5-1 is Dm-G7-C
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The series given is an arithmetic progression consisting of 5 terms with a common difference of 5 and first term 5 → sum{n} = (n/2)(2×5 + (n - 1)×5) = n(5n + 5)/2 = 5n(n + 1)/2 As no terms have been given beyond the 5th term, and the series is not stated to be an arithmetic progression, the above formula only holds for n = 1, 2, ..., 5.
For Geometric Progression #1 = a = 5 #2 = ar = x #3 = ar^2 = y #4 = ar^3 = 40 We need to find 'r' To do this ,divide #4 by #1 , hence ar^3 / a = 40 / 5 Hence r^3 = 8 (Notice the 'a' cancels down to leave 'r^3' Cube root both sides Hence r = 2 When r = 2 #2 = ar = 5 X 2 = 10 = x #3 = ar%2 - 5 x 2^2 = 5 x 4 = 20 = y So the geometric progression is 5,x,y,40 = 5,10,20,40
It is an arithmetic progression. Elements of the sequence can be identified by substituting the values of n in the expression 3n + 5
5
2==5 and 5!=3 or (5-2)^2>=1