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What is the probability that the product of the numbers will be a multiple of 6?
Assuming 2 randomly selected positive integers are multiplied together, I came up with a 5 in 12 chance (41 2/3 percent ) Here's how I figured it: take the first number and divide by six and examine the remainder (called modulo 6). You have 6 different possibilities (0,1,2,3,4,5), each with a 1 in six chance of occurring. If mod 6 = 0, then the first number is a multiple by 6, and it doesn't matter what the 2nd number is; all products are multiples of 6 as well. If mod 6 = 1 or 5, then the 2nd number must be a multiple of six to get the product to be multiple of 6. The chance of the 2nd number a multiple of six is 1 in 6. If mod 6 = 2, then these are numbers like 2,8,14,20... They are even numbers, so if the second number is a multiple of 3, then the product is multiple of 6. The chance of the 2nd number a multiple of three is 1 in 3. Mod 6 = 3, then first number is multiple of 3 (like 3,9,15,21), and the second number must be even (chance is 1 in 2). Mod 6 = 4, then first number is like 4,10,16,22 It is an even number so the 2nd number must be multiple of 3 (chance is 1 in 3). So in order how I described, we have (1 + 1/6 + 1/6 + 1/3 + 1/2 + 1/3)*(1/6) which equals 5/12.
Which number is a multiple of 3 and 6?
Any multiple of 6 is a multiple of 3 and 6.
Is 320 a multiple for 6?
no 320 is not a multiple of 6.
Is 6 a multiple of 12?
No, it is a factor. 12 is a multiple of 6.
Is 6 a multiple of 332?
332 divided by 6 = 55.3333 reacurring and 6 is not a multiPle
What is the 1st and 2nd common multiple of 8 and 6?
24 and 48
What is the probability that the product of the numbers will be a multiple of 6?
Assuming 2 randomly selected positive integers are multiplied together, I came up with a 5 in 12 chance (41 2/3 percent ) Here's how I figured it: take the first number and divide by six and examine the remainder (called modulo 6). You have 6 different possibilities (0,1,2,3,4,5), each with a 1 in six chance of occurring. If mod 6 = 0, then the first number is a multiple by 6, and it doesn't matter what the 2nd number is; all products are multiples of 6 as well. If mod 6 = 1 or 5, then the 2nd number must be a multiple of six to get the product to be multiple of 6. The chance of the 2nd number a multiple of six is 1 in 6. If mod 6 = 2, then these are numbers like 2,8,14,20... They are even numbers, so if the second number is a multiple of 3, then the product is multiple of 6. The chance of the 2nd number a multiple of three is 1 in 3. Mod 6 = 3, then first number is multiple of 3 (like 3,9,15,21), and the second number must be even (chance is 1 in 2). Mod 6 = 4, then first number is like 4,10,16,22 It is an even number so the 2nd number must be multiple of 3 (chance is 1 in 3). So in order how I described, we have (1 + 1/6 + 1/6 + 1/3 + 1/2 + 1/3)*(1/6) which equals 5/12.
Which number is a multiple of 3 and 6?
Any multiple of 6 is a multiple of 3 and 6.
Why is multiple of 6 is also a multiple of 3?
because 6 is a multiple of 3
Is 87 a multiple of 6?
No, 87 is not a multiple of 6.
Is 320 a multiple for 6?
no 320 is not a multiple of 6.
Is 90 a multiple of 6?
Is 90 a multiple of 6
Is 6 a multiple of 6?
Yes., 6 is 6 multiplied by one, so it is a multiple of 6.
Is 6 a multiple of 12?
No, it is a factor. 12 is a multiple of 6.
What is 5th multiple of 6?
1st = 8 2nd = 12 3rd = 16 4th = 20 5th = 24 6th = 28 1st is not 4 as that is the number itself so is not a multiple.
Is 31233 a multiple of 6?
No, 31233 is not a multiple of 6. Multiples of 6 are even.
Is 1 a multiple of 6?
A multiple of 6 is any whole number that can be divided by 6 with no remainder. 1 divided by 6 is zero remainder one. Therefore, 1 is not a multiple of 6.
