On a standard Ethernet network, between any two devices that communicate (such as computers), you can't have more than 4 repeaters (this includes hubs).
"5-4-3" refers to a maximum of 5 segments; 4 repeaters; 3 segments with hosts on them.
3 feet 5 feet
There are infinitely many possible answers. Rule 1: Add 9 to Input Rule 2: Add 5 to 2*Input Rule 3: Add 1 to 3*Input Rule 4: Subtract -3 from 4*Input or, moving away from whole numbers, Add 3.8 to 2.3 times Input.
multiply by 5 add 4
The rule, using a polynomial function of the lowest order is Un = (12n3 - 36n2 - 145n + 413)/25
if you mean -5/3 - 4/5 the answer is -2.4 if you mean -5/3-4/5 the answer is -1.13 ((-5)/3) - (4/5) = -2.4667 (-(5/3)) - (4/5) = -2.4667
10 base-t
If you order 3 tomatoes, they'll deliver 4 and charge you for 5.
No, because the rule refers to segments as well as devices. This rule only applies to 10base networks; when higher speeds are used (100 and up) the 5-4-3 rule does not apply.
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1 2 2 3 3 3 4 4 4 4 5 5 5 5 5 6 6 6 6 6 6As shown above, a digit is repeated to match the value of that digit.
3 4 6 9 13 18...1....2....3....4......5
+3 -3 +4 -3 +5 -3
3 feet 5 feet
3 4 5 6 The next number is 1 plus the previous number So the pattern rule is the next number is n + 1
i0 = 4; in = in-1 - 3
the rule is plus 2 1/3
+3, -3, +4, -3, +5, -3, (+6, -3, +7, -3...)