pay attention in class,,,, think it thin it , think different
The infinite set of numbers characterised by 468*k where k is an integer.
Every number is divisible by any non-zero number such as 891. Any element of the set of numbers of the form 891*k, where k is an integer, is evenly divisible.
18
Split the number into its alternate digits.Sum the digits in each setIf the difference between their sums is zero (0) or divisible by 11 then the original number is divisible by 11.ExamplesIs 1289324 divisible by 11?Split into alternate digits: 1_8_3_4 and _2_9_2 Sum each set of digits:1_8_3_4 -> 1+8+3+4 = 16_2_9_2 -> 2+9+2 = 13Difference between the sums: 16 - 13 = 3, not divisible by 11; so original number 1289324 is not divisible by 11.Is 19407278 divisible by 11?Split into alternate digits: 1_4_7_7 and _9_8_2_6 Sum each set of digits:1_4_7_7 -> 1+4+7+7 = 19_9_0_2_8 -> 9+0+2+8 = 19Difference between the sums: 19 - 19 = 0; so original number 19407278 is divisible by 11.
All multiples of 32, which is an infinite number.
Pay attention in class... Ans: Construct DFA for strings divisible by 5. Draw transition diagram. Reverse all arrows. You'r done..! That's the DFA that will interpret strings in reverse...
solution of dfa that accept the set of all strings of 0's and 1's with a most one pair of consecutive 0's and atmost one pair of consecutive 1's solution of dfa that accept the set of all strings of 0's and 1's with a most one pair of consecutive 0's and atmost one pair of consecutive 1's solution of dfa that accept the set of all strings of 0's and 1's with a most one pair of consecutive 0's and atmost one pair of consecutive 1's
How can I get appointment?
by notes, not chords when i enumerate the positions, that is the instruction on how to place your finger lower do = 2nd set of strings, 1st fret " re = 2nd set of strings, 3rd fret " mi = 3rd set of strings (open) or 2nd set of strings, 5th fret " fa = 3rd set of strings, 1st fret " so = 3rd set of strings, 3rd fret " la = 4th set of strings (open) or 3rd set of strings, 5th fret " ti = 4th set of strings, 2nd fret do = 4th set of strings, 3rd fret re = 5th set of strings (open) or 4th set of strings, 5th fret mi = 5th set of strings, 2nd fret fa = 5th set of strings, 3rd fret so = 6th set of strings (open) or 5th set of strings, 5th fret la = 6th set of strings, 2nd fret ti = 6th set of strings, 4th fret higher do = 6th set of strings, 5th fret " re = 6th set of strings, 7th fret " mi = 6th set of strings, 9th fret " fa = 6th set of strings, 10th fret " so = 6th set of strings, 12th fret " la = 6th set of strings, 14th fret " ti = 6th set of strings, 16th fret " do = 6th set of strings, 17th fret if a note is in # or sharp, move 1 fret to the right, if in b or flat, to the left
There is only one prime number divisible by 3 and it is 3 itself which is a prime number.
50 is divisible by 1, 2, 5, 10, 25 and 50 in the set of whole numbers. In the set of real numbers, 50 is divisible by any number and the answer will be a whole number only if it is divided by the 6 numbers mentioned above.
Every number is divisible by any non-zero number. Any element of the set of numbers of the form 795*k, where k is an integer, is evenly divisible.
Every number is divisible by any non-zero number.Any element of the set of numbers of the form 3*k, where k is an integer, is evenly divisible.
Every number is divisible by any non-zero number.Any element of the set of numbers of the form 236*k, where k is an integer, is evenly divisible.
Every number is divisible by any non-zero number. Any element of the set of numbers of the form 4518*k where k is an integer is evenly divisible.
The number 945 is divisible by 3,7,5 and 9. An easy way to determine what number is divisible by a set of numbers is to multiply all the numbers in the set.3*9*7*5=945 The LCM is 315.
They are members of the infinite set of numbers of the form 23*k where k is an integer. Since the set is infinite, it is not possible to list them.