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Verified answer
To figure this out you should first express the numbers as the product of their prime factors:
27 = 3x3x3
45 = 3x3x5
The next step is to identify any common prime factors. Both numbers have two 3s as prime factors. Multiply these together and you get:
3x3 = 9
Thus 9 is the HCF of 27 and 45.
To find this, you need to split the numbers into their prime factors:
45 = 3x3x5
27 = 3x3x3
The next step is to identify any common prime factors. In this case, both numbers have two 3s as prime factors. Multiply these together and you get 9. Thus the HCF of 45 and 27 is 9.
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How do you get the least common multiple of 27 and 45?
LCM = product/HCF; the HCF of 27 and 45 is 9 so LCM is 27 x 45/9 ie 135.LCM is the smallest multiple of 2 numbers and can be found by factoring both numbers and multiplying the prime factors having the highest powers.Prime factors of 27 are 33Prime factors of 45 are 32 x 5LCM of 27 and 45 is 33x 5 = 135
What is the HCF of 45 and 40?
The hcf of 45 and 40 is 5.
What are the HCF of 45 9 and 8?
The HCF is 1.
What is the HCF of 5 and 9?
The GCF is 1.
What is the HCF of 27 and 54?
27
What is the HCF of 108 and 27?
27
What is the hcf of 81 and 27?
It is: 27
What is the HCF of 26 and 45?
HCF(26, 45) = 1. The numbers are co-prime.
What is the HCF of 75 and 45?
The GCF is 15.
What is HCF of 27 and 81?
The GCF is 27.
What is the GCF of 27 45 and 63 using a factor tree?
gcf(27, 45, 63) = 9. 27 = 3 x 3 x 3 45 = 3 x 3 x 5 63 = 3 x 3 x 7 hcf = 3 x 3 = 9
What is the HCF of 45 and 55?
The GCF is 5.
