13y-6
y = 6 * ( x + 11)
42 divided by 7 is 6. 7y = 42 Divide both sides by 7. y = 6.
abs(y^3 - 4) < 8*y
x + y = 19, so x = 19 - y; xy = 78; Substituting gives 19y - y2 = 78 ie y2 - 19y + 78 = 0. This factorises as (y - 13)(y - 6) so the smaller number is 6 and the other is 13.
13y-6
y = 6 * ( x + 11)
We will get two values of y . One is y=6 and another is y=13
42 divided by 7 is 6. 7y = 42 Divide both sides by 7. y = 6.
6x - (6 + y)
(6 * y) +9
y + 6 + 6 = 15 15-6-6 = y 9-6 = y 3 = y
Y+6
0.34*y
(xy)+6
There is no such thing as the product of just one number, a product is when 2 or more numbers are multiplied. The product of a number and another number means the answer you get when you multiply the two.
abs(y^3 - 4) < 8*y