Flexible steel wire rope (FSWR)
To calculate the SWL in kilograms of FSWR square the rope diameter (D) in millimetres (mm) and multiply by 8.
Formula: SWL (kg) = D2(mm) x 8
Rope dia (D) = 12 mm
SWL(kg) =D2 (mm)x8
= D (mm) x D (mm) x 8
= 12 x 12 x 8
= 1152 kg SWL (t) = 1.15 tonnes
The above equation can be reversed to calculate the diameter (D) in millimetres of FSWR needed to lift a given load. To do this, divide the load (L) in kilograms by 8 and find the square root of the result.
Formula: D(mm) = √L(kg) 8
Load = 1152 kg
D (mm) = √1152 ÷ 8 = √144
= 12 (mm)
Therefore a FSWR sling of at least 12 mm in diameter is required to lift a 1152 kg load for a straight lift.
The SWL stands for - Safe Working Load
SWL means Safe Working Load
The initials SWL mean Safe Working Load
TO CALCULATE THE SWL OF LIFTING WIRE ROPE THE FORMULAE CAN BE USED- 8*D2 WHERE 'D' IS THE DIAMETER OF WIRE ROPE IN 'mm' THIS WILL GIVE THE APPROX SWL (SAFE WORKING LOAD CAPACITY)
Sean Walter Lopez
1.6 ton The answer would be 40T, 1.6T is the WLL or SWL of an 8T nominal breaking strength rope.
Yeah! (D X 8), where, D= Diameter!
If SLI is in operating condition then sLI itself will indicates that whether load is in safe mode. But if SLI is not working then one must be considered 40 % factor of safety of crane SWL and in SLI working condition it will be considered 20 % of its SWL.
Cranes typically are designed with a FoS (Factor of Safety) of 5x the MBL (Minimum Breaking Load). So if the weakest part of the structure failed (e.g. in tension, compression or shear) at e.g. 100kN (10 metric tons), then the swl would be 10t / 5 = 2 tons
J. C. Gillespie has written: 'SWL address book' -- subject- s -: Directories, Shortwave radio stations