What is the SWL of FSWR?

Answer 1

Flexible steel wire rope (FSWR)

To calculate the SWL in kilograms of FSWR square the rope diameter (D) in millimetres (mm) and multiply by 8.

Formula: SWL (kg) = D2(mm) x 8

For example:

Rope dia (D) = 12 mm

SWL(kg) =D2 (mm)x8

= D (mm) x D (mm) x 8

= 12 x 12 x 8

= 1152 kg SWL (t) = 1.15 tonnes

The above equation can be reversed to calculate the diameter (D) in millimetres of FSWR needed to lift a given load. To do this, divide the load (L) in kilograms by 8 and find the square root of the result.

Formula: D(mm) = √L(kg) 8

For example:

Load = 1152 kg

D (mm) = √1152 ÷ 8 = √144

= 12 (mm)

Therefore a FSWR sling of at least 12 mm in diameter is required to lift a 1152 kg load for a straight lift.