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Assume the car has constant acceleration a and initial velocity 0. Then the velocity at time t will be a*t, so if we call the distance travelled at time t, x, we get the following identity:

a*t = dx/dt

This differential equation can be solved in any number of ways to yield

1/2 * a * t^2 = x

where the constant of integration is zero since the distance travelled at time 0 is 0 by definition.

Therefore we have:

a = 2*x/t^2 = 2*5m/(4.5s)^2 = 40/81 ms^-2

or about half a meter per second squared

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