Order of operations has the multiplication happen first and then the addition.1+1+1+1+1+1+1x0+1=1+1+1+1+1+1+0+1=7All the addition can happen in the same step.
1
Anything multiplied by zero is zero - no matter how complex the sum !
14
ANY number multiplied by 0 = 0.
Order of operations has the multiplication happen first and then the addition.1+1+1+1+1+1+1x0+1=1+1+1+1+1+1+0+1=7All the addition can happen in the same step.
1
Anything multiplied by zero is zero - no matter how complex the sum !
Multiplication and division first, addition and subtraction second. Without brackets, that equation equals 2.
14
7
7
2, realiza-se a multiplicação primeiro
7 6 - 1 x 0 + 1 1. Multiplication first (PEMDAS), 1x0 = 0 2. Division, Addition, Subtraction.... 6-0+1= 7
ANY number multiplied by 0 = 0.
6-1x0+2/2=7 Order of operations requires that multiplication and division be performed first. 6-(1x0)+(2/2)=7 I've added parenthesis to make the math a bit clearer. 6-(0)+(1)=7 And Voila, the answer is 7.
7. But, the answer can also be 4. This is an ambiguous question. If the question is interpreted in this way : 6- (1x0) + (2/2), then the answer is 1 [6-0+1 = 7]. But, if the question is interpreted as : [6-(1x0) + 2]/2 ------- when the whole term is divided by two, the answers is 2 [(6-0+2)/2 = 8/2 = 4].