The answer to 55 hundreds and 16 ones is 5616. In this case, you would combine the hundreds place value (50) with the ones place value (16) to get the final number. This is a way of representing a number in expanded form, where each digit's place value is explicitly stated.
668
The number that has 3 hundreds, 20 tens, and 16 ones can be written as 320 + 16 = 336. In this number, there are 3 hundreds (300), 20 tens (20 x 10 = 200), and 16 ones. When you add these together, you get the final number, 336.
7 hundreds, 16 tens 4 ones is 7 x 100 + 16 x 10 + 4 x 1 = 700 + 160 + 4 = 864.
300+16+5=321
ones 5 hundreds is 7 hundreds, thanks now, bye
668
375
The number that has 3 hundreds, 20 tens, and 16 ones can be written as 320 + 16 = 336. In this number, there are 3 hundreds (300), 20 tens (20 x 10 = 200), and 16 ones. When you add these together, you get the final number, 336.
7 hundreds, 16 tens 4 ones is 7 x 100 + 16 x 10 + 4 x 1 = 700 + 160 + 4 = 864.
465
300+16+5=321
16% of 55= 16% * 55= 0.16 * 55= 8.8
Need to know The answer
It is 16*10 + 8*1 + 2*100 = 160 + 8 + 200 = 368.
Because 300+50+6 = 356 and 300+40+16 = 356
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
ones 5 hundreds is 7 hundreds, thanks now, bye