0
What else can I help you with?
What is the answer to 12x plus 6-8x-4x-3 plus 12?
If the equasion is 12x+6-8x-4x-3+12 then the answer is 15.
X2 plus 8x plus 16 equals?
(x + 4)(x +4) or (x + 4)squared
Y-8x plus 9y equals?
Y-8x plus 9y equals 10y-8x.
What is the square root of 8x squared plus 16 minus 3x equals 0?
the answer of √8x+16-3x=0 is x= 0.447213595 = +/- 0.447(to 3 decimal places) if I'm not mistaken
8x-7 plus 2x equals 6 plus 5x plus 2?
8x-7 plus 2x equals 6 plus 5x plus 2?
What is negative 4x squared plus 12x squared?
8x squared
What is the answer to 8x-3 plus 6x-1 equals 12x plus 6?
8x-3+6x-1 = 12x+614x-4 = 12x+614x-12x = 6+42x = 10x = 5
12x plus 7 equals 8x plus 23?
Subtract 7 from each side: 12x = 8x + 16Subtract 8x from each side: 4x = 16Divide each side by 4: x = 4
Factor 8x cubed plus 2x squared plus 12x plus 3?
The answer is (2x^2+3)(4x+1)
8x-1 equals -4x plus 23?
8x-1 = -4x+23 8x+4x = 23+1 12x = 24 x = 2
What is the answer to 12x plus 6-8x-4x-3 plus 12?
If the equasion is 12x+6-8x-4x-3+12 then the answer is 15.
What is the square root of x squared plus 12x -2 equals x plus 4?
It's a second-degree equation in 'x' that screams "trouble". But we laugh in theface of adversity and, with no thought for our personal safety, we plunge right inand pursue solution[s].sqrt( x2 + 12x - 2) = x + 4Square each side . . . . . . . . . . x2 + 12x - 2 = x2 + 8x + 16Subtract x2 from each side . . . 12x - 2 = 8x + 16Add 2 to each side . . . . . . . . . 12x = 8x + 18Subtract 8x from each side . . . 4x = 18Divide each side by 4 . . . . . . . . x = 9/2
What is 4x plus 8x plus 3?
4x+8x+3 = 12x+3
X2 plus 8x plus 16 equals?
(x + 4)(x +4) or (x + 4)squared
What is x squared minus 8x plus 8y plus 32 equals 0 in standard parabola form?
x^(2) + 8x + 8y +32 = 0 Then -8y = x^(2) + 8x + 32 y = (-x^(2)/8) - x - 4 In standard parabolic form. The coefficient of x^(2) is '-1/8' . It will be an 'umbrella' shaped parabola.
What is 8x plus y plus 4x plus 2y?
It simplifies to: 12x+3y
Factor x squared - 8x plus 12 equals 0?
(x - 6)(x - 2)
