There is no solution to: 4(2x + 2) + 12 > 1004(2x + 2) + 12 > 100 For 4(2x + 2) + 12 > 1004(2x + 2) + 12 to have a solution x < -1 which makes 1004(2x + 2) + 12 < 12, BUT 1004(2x + 2) + 12 is supposed to be greater than 100. Perhaps there is a missing operator in the digits of 1004?
2x-3=4x+9 -2x-12=0 2x=-12 x=-6
2x/3y
2x-4=6x+8-8= -82x-12= 6x-2x= -2x-12= 4x/4=/4-3=x
2x-3=9 so 2x=12 and x=6
14
x = 1
10
4x + 12 = 2x - 2Subtract 2x from each side:2x + 12 = -2Subtract 12 from each side:2x = -14Divide each side by 2:x = -7
2x+10=12 2x=2 x=1
2x +n5y=12
There is no solution to: 4(2x + 2) + 12 > 1004(2x + 2) + 12 > 100 For 4(2x + 2) + 12 > 1004(2x + 2) + 12 to have a solution x < -1 which makes 1004(2x + 2) + 12 < 12, BUT 1004(2x + 2) + 12 is supposed to be greater than 100. Perhaps there is a missing operator in the digits of 1004?
Do you mean 2x²? Assuming this is the case: 2x² - 3x + 8x - 12 = 2x² + 5x - 12 = (2x - 3)(x + 4)
As written, that's 2(x - 6) You may have meant 4x^2 - 2x - 12 which would be 2(2x + 3)(x - 2)
2x-3=4x+9 -2x-12=0 2x=-12 x=-6
2x-2 = 10 2x= 10+2 2x=12 x= 12/2 x=6
2x+12=2(x+6)