1 x 36 = 36 2 x 36 = 72 3 x 36 = 108 4 x 36 = 144 5 x 36 = 180 6 x 36 = 216 7 x 36 = 252 8 x 36 = 288 9 x 36 = 324 10 x 36 = 360 11 x 36 = 396 12 x 36 = 432
(6 x 10^12)^2 = 6^2 x (10^12)^2 = 36 x 10^24 = 3.6 x 10^25.
3 x 10 = 30 + 3 x 2 = 6 3 x 12 = 36
9 x 4 = 36 18 x 2 = 36 3 x 3 x 2 x 2 = 36
36 = 4 x 9 => 36 = 2 x 2 x 3 x 3=> 36 = 2^(2) X 3^(2)
1 x 36 = 36 2 x 36 = 72 3 x 36 = 108 4 x 36 = 144 5 x 36 = 180 6 x 36 = 216 7 x 36 = 252 8 x 36 = 288 9 x 36 = 324 10 x 36 = 360 11 x 36 = 396 12 x 36 = 432
(6 x 10^12)^2 = 6^2 x (10^12)^2 = 36 x 10^24 = 3.6 x 10^25.
36 cards, numbered 2-10, x 4 suits.
3 x 10 = 30 + 3 x 2 = 6 3 x 12 = 36
The LCM of 18, 10 and 12 is 180. 18 = 2 x 3^2 10 = 2 x 5 12 = 2^2 x 3 lcm = 2^2 x 3^2 x 5 = 180
9 x 4 = 36 18 x 2 = 36 3 x 3 x 2 x 2 = 36
12 x 18 = 216 10 x 18 = 180 2 x 18 = 36 180 + 36 = 216
36 as a product of its prime factors is 2 x 2 x 3 x 3. Their total is 10. 36 as a product of factors that total 13 is 4 x 9
The prime factors of 36 are: 1, 2, 18, & 36 1 x 36 & 2 x 18
36 = 2 x 2 x 3 x 3
36 = 4 x 9 => 36 = 2 x 2 x 3 x 3=> 36 = 2^(2) X 3^(2)
Let the number of pigs be x. So the number of ducks will be 10 - x. Since pigs have 4 legs and ducks have 2 legs, then we have 4x + 2(10 - x) = 36. Solve for x: 4x + 20 - 2x = 36 2x + 20 = 36 subtract 20 to both sides 2x = 16 divide by 2 to both sides x = 8 10 - x = 10 - 8 = 2 Thus, there are 8 pigs and 2 ducks. Check: