3x+1+2x-2 = 64 3x+2x = 64-1+2 5x = 65 x = 13
If: x3+1 = 65 Then: x3 = 65-1 And: x3 = 64 So: x = 4 by means of the cube root function on the calculator
Subtract 1 from each side: x3 = 64; You might know that 4 cubed is 64, but if you don't then take log 64, divide it by 3 and take the antilog of your answer...
64-3 equals = 61
Nothing. If it's -65, you can use 65 and -1.
R = 65*e-5k = 65/(0.006738)k
x2 - 2x + 65 = 0 Subtract 64 from each side: x2 - 2x + 1 = -64 (x - 1)2 = (i*8)2 where i is the imaginary square root of -1 x - 1 = +/- 8i x = 1 +/- 8i
They are: 12+82 = 65 or as 1+64 = 65
Yes, 65 is greater than 63.
65/65=1+65=66
How about: 8*8 = 64
16