It is: (5+4) times 8 = 72
-4 and +12
8 x (4 + 2) = 48
find the sum and product of the roots of 8×2+4×+5=0
8(5+4)+7 = 79
7/8 > 4/5 ? (cross multiply)7 x 5 > 4 x 8 ?35 > 32So that 7/8 > 4/5.
well the sum would be 4+8=12 the difference would be 8-4=4 so multiply those and you get 4x12=48
The answer is -32 Sum of -16+8 = -8 Half of -8 = -4 Sum of -5+9 = 4 Twice of 4 = 8 Product = 8*(-4) = -32
You need to perform the same sum on the numerator and denominator for example multiply the fraction by 2;4/5 (4 x 2=8) (5 x 2=10) 8/10Therefore, 4/5 is equivalent to 8/10.
-4 and +12
8 x (4 + 2) = 48
solve anything in brackets before anything else. ex: [7+2(9-4)]8 you would do the 7+2 first, (9) then the parenthesis (5) then multiply the 9 and the 5 (45) and then multiply that by 8 (360)
Multiply 6 and 4. Multiply 8 and 3.
Answer is 8 (4 multiply 10 devide by 5 ) then you get 8
find the sum and product of the roots of 8×2+4×+5=0
The sum of 7/8 and 3/4 is 1 5/87/8 + 6/8 = 13/8 = 1 and 5/8
to sum two numbers you add them together then to get twice that you multiply the sum by 2 e.g. if the two numbers are 5 and 8 the sum = 5 + 8 = 13 twice that is 13 x 2 = 26
-4 minus 8 plus 5 is equal to -7