It is: (5+4) times 8 = 72
-4 and +12
The sum of 8 and 5 is 13 The difference of 8 and 5 is 3 So the question is what is the product of 13 and 3 13 X 3= 39
8 x (4 + 2) = 48
-2
find the sum and product of the roots of 8×2+4×+5=0
well the sum would be 4+8=12 the difference would be 8-4=4 so multiply those and you get 4x12=48
The answer is -32 Sum of -16+8 = -8 Half of -8 = -4 Sum of -5+9 = 4 Twice of 4 = 8 Product = 8*(-4) = -32
-4 and +12
You need to perform the same sum on the numerator and denominator for example multiply the fraction by 2;4/5 (4 x 2=8) (5 x 2=10) 8/10Therefore, 4/5 is equivalent to 8/10.
The sum of 8 and 5 is 13 The difference of 8 and 5 is 3 So the question is what is the product of 13 and 3 13 X 3= 39
8 x (4 + 2) = 48
To multiply the sum of 16 and 9 by 8, first calculate the sum of 16 and 9, which is 25. Then, multiply 25 by 8. The result is 200. So, (16 + 9) × 8 = 200.
-2
solve anything in brackets before anything else. ex: [7+2(9-4)]8 you would do the 7+2 first, (9) then the parenthesis (5) then multiply the 9 and the 5 (45) and then multiply that by 8 (360)
Multiply 6 and 4. Multiply 8 and 3.
Answer is 8 (4 multiply 10 devide by 5 ) then you get 8
find the sum and product of the roots of 8×2+4×+5=0