How approximate do you want?
√38 ≈ 6
√38 ≈ 6.2
√38 ≈ 6.16
√38 ≈ 6.164
√38 ≈ 6.1644
√38 ≈ 6.16441
√38 ≈ 6.164414
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The square root of 1,444 is: 38
± 38
√-48 + 35 + √ 25 + √-27 = √[(i2)(16)(3)] + 35 + 5 + √[(i2)(9)(3)] = 4i√3 + 38 + 9i√3 = 38 + (13√3)i
Assuming you mean consecutive numbers are integers, then: The integers will be the two integers between which the square root of 1406 lies. Calculating the square root of 1406 using the "long" division method: ________3__7 _____---------- ___3|_14_06 ________9 _______--- __67|__506 ________469 ________---- _________37 The square root of 1406 is 37.<something>, thus it lies between 37 and 38, so: 1406 = 37 × 38
what is the value of the 3 in 38