The lengths of the sides of a parallelogram is not enough information to determine its area.
The area of a rectangle is found by multiplying its length by its width. 6 ft x 4 ft = 24 sq ft.
38 yd 2
4 ft 11 in = 149.86 cm.
4 ft.
The area of any triangle is defined as half the base multiplied by the height.
Parallelogram area = bh = 11 in x 4 in = 44 in^2
Area = 0.5*4*11 = 22 square feet
Area = side^2 side = √121 = 11 ft Perimeter = 4 x side = 4 x 11 = 44 ft.
Area = side^2 side = √121 = 11 ft Perimeter = 4 x side = 4 x 11 = 44 ft.
It depends on what the 4 measures given are! If they are the lengths of the sides of a parallelogram, the question cannot be answered.
358 ft2
1 ft = 12 in → 11 ft 4 in = 11 × 12 in + 4 in = 132 + 4 in = 136 in > 135 in → 11 ft 4 in > 135 in → Yes, 11 ft 4 in is "bigger" than 135 in.
Yes becauseThe area of a parallelogram can be found by multiplying the base times the height.If a parallelogram has a base of length 6 inches and a height of 4 inches, its area is 6*4=24 square inches
What is the area of a parallelogram with a base of 4 meters and a height of 10 meters?
Area = (1/4)*Ï€*d2 where d is the diameter. So area = pi*121/4 = 95.033 sq ft (to 3 dp)
Area = 4*13 = 52 square yards
The area of a rectangle is found by multiplying its length by its width. 6 ft x 4 ft = 24 sq ft.