Squares have 4 equal sides. So lets set x equal to one of the sides of the square.
x = one side of the square
The perimeter of a square is the distance around the outside. This is equal to the sum of the lengths of the sides. Because a square has 4 sides the perimeter is as follows
4x = perimeter
Solving for x in this case gives you 7.
The area of any rectangle is equal to the base * height. In a square this means side * side or side2.
area = x2
Solving for the area in the case given we find that the area of a square with a perimeter of 28 is equal to 49 units2
The perimeter will be 28.
The area of square is : 784.0
The perimeter would be 28 cm
The area of square is the square of one of its sides, which are all equal. To find the value of a side, take the square root of the area. In this case the square root of 49cm2 is 7cm. The perimeter is the sum of all four sides of the square, so the perimeter of a square with an area of 49cm2 is 7+7+7+7 = 28, or 4x7 = 28.
To fence an area is equivalent to finding its perimeter. Since the area of a square = length*width, it must be that the square root of its area is the length of a side, which is sqrt(28). Since there are four sides in a square, the perimeter is equal to 4sqrt(28) = 21.66m I'm sure the question states that the square's side (not area) is 28 metres. In that case, perimeter = 4*28 = 112 metres.
If the perimeter of a square is 28 inches the area is: 49 square inches.
If square has a 28-inch perimeter its area is: 49 square inches.
The perimeter will be 28.
The perimeter is 28.
The area of square is : 784.0
The area is 49 square units.
The perimeter would be 28 cm
Its area is 49 square inches.
It is: 28 units
A = 49 square inches.
28 cm
49 square centimetres.