Oh, dude, you just add them up and divide by how many numbers there are. So, like, 51 + 52 + 56 = 159, and since there are three numbers, you divide 159 by 3 and get 53. So, the average is 53.
the average of 51, 52, and 56 is 53
you minus the largest number by the smallest. So 56-48=8. The answer is 8.
It is 52, the middle number when they are in order.
when you put the numbers in order as described the number in the middle is the median. If 2 numbers are in the middle as in this case 56 and 58 you average them and get 57 as the median
52, 54, and 56. I would include 58, but the word 'between' means that it can not include the numbers on the ends (51 and 58).
56 * 52 = 2912
The average of the numbers 51, 52, and 56 is 53. To get the average you would add all three numbers and then divide by three.
you minus the largest number by the smallest. So 56-48=8. The answer is 8.
It is 52, the middle number when they are in order.
the average age is 40
52, 54, 55, 56, 57, 58
when you put the numbers in order as described the number in the middle is the median. If 2 numbers are in the middle as in this case 56 and 58 you average them and get 57 as the median
52, 54, and 56. I would include 58, but the word 'between' means that it can not include the numbers on the ends (51 and 58).
51 + 56 = 107
50. 51. 52. 53. 54. 55. That is 6 numbers.
49, 50, 51, 52, 54 and 55 are the composite numbers between 48 and 56.
56 * 52 = 2912
51-LI 52-LII 53-LIII 54-LIV 55-LV 56-LVI 57-LVII 58-LVIII 59-LIX 60-LX