10
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10+14+9=33 average=33\3=11
14
Average = (6 + 10 + 56 + 8)/4 = 20
To find two numbers with a mean of 10 and a range of 8, we can set up a system of equations. Let x be the smaller number and y be the larger number. We know that (x+y)/2 = 10 (mean of 10) and y-x = 8 (range of 8). Solving these equations simultaneously, we get x = 6 and y = 14. Therefore, the two numbers are 6 and 14.
The two numbers are 10 and -4 because 10+(-4) = 6 and 10-(-4) = 14