The answer to average of 6 10 56 and 104 would be 44
The answer is 44 because 6+10+56+104=176 176/4=44
Average = (6 + 10 + 56 + 8)/4 = 20
104
Solve:4 - 3x = 104 - 3x - 4 = 10 - 4-3x = 6-3x/-3 = 6/-3x = -2Check:4 - (3 x -2) = 104 - (-6) = 104 + 6 = 1010 = 10
The answer to average of 6 10 56 and 104 would be 44
The answer is 44 because 6+10+56+104=176 176/4=44
Average = (6 + 10 + 56 + 8)/4 = 20
It is 33, the number halfway between the two middle numbers when they are listed in order.
104
Solve:4 - 3x = 104 - 3x - 4 = 10 - 4-3x = 6-3x/-3 = 6/-3x = -2Check:4 - (3 x -2) = 104 - (-6) = 104 + 6 = 1010 = 10
12*56 Use the distributive property on 12: (10+2)*56 = 10*56 + 2*56 Use the distributive property on 56 twice: 10*(50+6) + 2*(50+6) = 10*50 + 10*6 + 2*50 + 2*6 = 500 + 60 + 100 + 12 = 672
-5a + 6 = 56 Dubtrt '6' from both sides -5a = 50 Divifer both sides by '-5' a = -10 Note the negstive answer.
104 / 2 = 52 104 / 3 = 34.666666666666666666 104 / 5 = 20.8 104 / 6 = 17.333333333333333333 104 / 9 = 11.555555555555555555 104 / 10 = 10.4 The answer to this question is YES but.Going further the no. 144 is divissible by 2 without remainder.The but aspect of it is that it can be divided by:3,5,6,9 and10 but with remainders.
.56 = 0 + (5/10) + (6/100)
out of 60 = 56 out of 10 = 56/6 = 9.333 out of 100 = 93.33
4, 6, 8, 9, 104, 6, 8, 9, 10