First, you must add all five numbers. If you do so, you should get 390.
Then, you divide the sum of the numbers (390) by the amount of numbers you have (5).
390 divided by 5 gives you 78.
93
It is: 89/99
8811.
9 19 29 39 49 59 69 79 89 90 91 92 93 94 95 96 97 98 99 Answer: 20 (99 has 2 9's)
99 x 10 - 99 x 9 = 99(1 x 10 - 1 x 9) = 99(10 - 9) = 99(1) =99
93
well the answer is 84.6 how we get the answer is adding up all of the variables 63, 79, 89, 93, 99 and we get 423 now we divid that total by the amount of varibles in this case 5 and we get our answer 84.6
The average of 99 percent and 93 percent is 96%solve= 99+93=192 /2= 96 Ans
109
99
She needs a total of 5 x 95 ie 475 over the five tests. She has 376 so far, so she needs 99 in the next test. 93+89+96+98=376 she wishes to raise her average to 95=> 5x95=475 475-376=99
89
99
The average of nine numbers is 99, that is tha the sum of those numbers was 99 x 9, which is 891. The average of 8 numbers is 89, that is that the sum of those numbers was 89 x 8, which is 712. So, 891 - 712 = 179 The number that was deleted was 179.
It is: 89/99
90 91 92 93 94 95 96 98 99 100
The integers greater than 10 but less than 100 start from 11 and go up to 99. To find the count of these integers, subtract 10 from 99, which gives 89, and then subtract 1 (to exclude 10 itself), resulting in 89 - 10 = 89. Thus, there are 89 integers greater than 10 but less than 100.