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What is the Acceleration of a car that got up to 45 ms from a rest position in 3 seconds?
Velocity at time 0 sec = 0m per sec Velocity at time 3 sec = 45m per sec Acceleration is 45/3 = 15m per sec if the acceleration is uniform
When mass is decreased?
An object travelling at a velocity close to the speed of light had a higher mass than when at rest.
What does a horizontal line on a distance-time graph indicate?
It means there is no velocity - it is at rest and nothing is moving. The slope of the line is velocity - a horizontal line is zero slope = zero velocity
How long would it take to count to a billion?
It depends on how fast you're counting. Answer: Although lower numbers (1, 2, 3 etc.) can be said in a second or less, larger numbers like 999,999,999 take up to 5 seconds to say. Assuming that an average value would be 4 seconds the time required would be 4 billion seconds if you didn't stop or rest. This is the same as 127 years.
A 12 kg rocks falls from rest off a cliff and hits the ground in 1.5 s.without considering air resistance what is the rock s velocity just before it hits the ground?
The velocity is gravity acceleration x time or (9.8)(1.5) = 14.7 m/s. The velocity is not dependent on the mass.
What is the momentum of a resting particle?
Momentum = (mass) x (velocity)If the particle is at rest, velocity = 0, and momentum = 0.
When average velocity is equal to its instantaneous velocity acceleration?
you are still. motion is at rest.
What is the objects average velocity over a 15 second interval if the object initially at rest experiences an acceleration of 1.7 for 6 sec and travels at that constant velocity for another 9 seconds?
Average velocity is total distance by total time . let us calculate velocity at the end of 6 seconds. v=vo+at v= 0+1.7*6 v=10.2 m/sec distance travelled by object in six seconds x= vot+1/2at2 x=0+.5(1.7)(62) x=30.6 m the final velocity at the end of six seconds that is 10.2m/s will be the initial velocity when objects moves with uniform velocity with a constant velocity x= vot+1/2at2 . . . accel is 0 since velocity is constant between 6 & 15 secs. x=10.2*9=91.8 Again . . average velocity is total distance by total time. Average velocity= [30.6+91.8]/15= 122.4*15 = 8.16m/s
How are a body at rest and body moving similar in velocity?
A body at rest and a body in motion have completely different velocities.Magnitude of velocity:At rest . . . zeroMoving . . . not zeroDirection of velocity:At rest . . . no directionMoving . . . some direction
What is the velocity of an object that started from rest and has been in free fall for 10 seconds?
The velocity of an object in free fall after 10 seconds is approximately 98 m/s. This value is the acceleration due to gravity (9.8 m/s^2) multiplied by the time in seconds.
What will be the total energy of a particle of rest mass m and momentum p moving at velocity close to light?
The total energy of a particle with rest mass m and momentum p moving at a velocity close to the speed of light is given by Einstein's equation: E^2 = (pc)^2 + (mc^2)^2, where c is the speed of light. Since the particle is moving at a velocity close to light, its total energy will be dominated by its momentum term (pc)^2.
What happens when a particle is freed from rest?
When a particle is freed from rest, it will start to move due to the absence of any external forces holding it in place. This movement is known as acceleration, which is the change in velocity over time. The particle will continue to move until it encounters another force that acts upon it, causing it to change direction or speed.
What is the final velocity of a train that starts at rest and accelerates for 15.0 seconds at an average acceleration of 2.40 meter per second squared?
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
A car starts at rest and attains a velocity of 15 meters per second in 5 seconds what is its acceleration?
The average acceleration is given by the expression a ∆v/∆t (15 m/s)/5s 3m/s2 where a is acceleration, v is velocity, and t is time. ∆ (final-initial) value.
What is the time required to determine the time for a drop, starting from rest, to reach 63 of terminal velocity?
The time required to determine the time for a drop, starting from rest, to reach 63 of terminal velocity is typically around 5 to 6 seconds.
What is the angular velocity of the wheel before braking began if the wheel rotates through 6 radians in 2 seconds as it is uniformly brought to rest?
It was 6 radians per second. Angular acceleration = -3 radians per second2 Initial angular velocity = 6 radians per second. Final angular velocity = zero. Average angular velocity = 3 radians per second. Angular displacement in 2 seconds = 3 x 2 = 6 radians.
A sprinter explodes out of the starting block with an acceleration pf 2.3 ms2 which she sustains for 1.2 sThenher acceleration drops to zero for the rest of the raceWhat is her velocity at1.2s?
The sprinter's velocity at 1.2 seconds can be calculated using the formula: velocity = initial velocity + acceleration × time. Given the initial velocity is 0 m/s, acceleration is 2.3 m/s^2, and time is 1.2 seconds, the velocity at 1.2 seconds would be 2.76 m/s.
