Velocity at time 0 sec = 0m per sec Velocity at time 3 sec = 45m per sec Acceleration is 45/3 = 15m per sec if the acceleration is uniform
An object travelling at a velocity close to the speed of light had a higher mass than when at rest.
It means there is no velocity - it is at rest and nothing is moving. The slope of the line is velocity - a horizontal line is zero slope = zero velocity
It depends on how fast you're counting. Answer: Although lower numbers (1, 2, 3 etc.) can be said in a second or less, larger numbers like 999,999,999 take up to 5 seconds to say. Assuming that an average value would be 4 seconds the time required would be 4 billion seconds if you didn't stop or rest. This is the same as 127 years.
The velocity is gravity acceleration x time or (9.8)(1.5) = 14.7 m/s. The velocity is not dependent on the mass.
The momentum of a resting particle is zero, as momentum is the product of an object's mass and velocity, and velocity is zero when the particle is at rest.
you are still. motion is at rest.
The average velocity can be calculated as the total displacement of the object divided by the total time taken. The object's total displacement during the acceleration phase can be calculated using the equation for uniformly accelerated motion. For the remaining 9 seconds, the object travels at a constant velocity, so the average velocity will be the same as this constant velocity. Calculate the total displacement for the acceleration phase and divide by the total time (15 seconds) to find the average velocity.
Both a body at rest and a body moving have a velocity of zero at a single point in time. The difference lies in their average velocities over a period of time - a body at rest maintains a constant velocity of zero, while a body in motion will have a non-zero average velocity over that period.
The velocity of an object in free fall after 10 seconds is approximately 98 m/s. This value is the acceleration due to gravity (9.8 m/s^2) multiplied by the time in seconds.
The total energy of a particle with rest mass m and momentum p moving at a velocity close to the speed of light is given by Einstein's equation: E^2 = (pc)^2 + (mc^2)^2, where c is the speed of light. Since the particle is moving at a velocity close to light, its total energy will be dominated by its momentum term (pc)^2.
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
The average acceleration is given by the expression a ∆v/∆t (15 m/s)/5s 3m/s2 where a is acceleration, v is velocity, and t is time. ∆ (final-initial) value.
It was 6 radians per second. Angular acceleration = -3 radians per second2 Initial angular velocity = 6 radians per second. Final angular velocity = zero. Average angular velocity = 3 radians per second. Angular displacement in 2 seconds = 3 x 2 = 6 radians.
The sprinter's velocity at 1.2 seconds can be calculated using the formula: velocity = initial velocity + acceleration × time. Given the initial velocity is 0 m/s, acceleration is 2.3 m/s^2, and time is 1.2 seconds, the velocity at 1.2 seconds would be 2.76 m/s.
To determine the velocity of the ball 0.6 seconds after its release, we need more information such as the initial velocity and acceleration of the ball. You would use the formula: velocity = initial velocity + (acceleration * time).
The average acceleration can be calculated using the equation of motion: average acceleration = (final velocity - initial velocity) / time. Plugging in the values, we get: average acceleration = (26.3 m/s - 0 m/s) / 0.59 s ≈ 44.6 m/s^2.