Eleven.
The furthest right side is the 2^0 = 1's place, there is a 1 here so we start with 1
The second furthest right place is the 2^1 = 2's place, there is a 1 here so we add 2
The second place from the left is the 2^2 = 4's place, there is a 0 here so we add nothing
The leftmost place is the 2^3 = 8's place, there is a 1 here so we add 8.
Totaling up, we have 1 + 2 + 0 + 8 = 11
I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).
Converted to decimal, the binary number 10111011 would be expressed as 187. If the space in the question indicates a separation between two numbers, then "1011 1011" would be expressed in decimal notation as "11 11".
I do not believe that is a valid binary number. All binary numbers must be divisible by 8
The decimal equivalent of the binary number 10110000 is 176
1011 0011
The number 11 in binary is 1011
110
I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).
1011 = 11
Decimal 11 = binary 1011
11
Converted to decimal, the binary number 10111011 would be expressed as 187. If the space in the question indicates a separation between two numbers, then "1011 1011" would be expressed in decimal notation as "11 11".
11 in binary form: 1011 11 is binary form of 3
When you add 1011 and 1101 in the binary system, you get 11000. To calculate this, start by adding the rightmost digits, which are 1+1=10 in binary (0 carry 1). Then, move to the left, adding the next digits along with any carries until you reach the leftmost digit. The result is 11000 in binary.
I do not believe that is a valid binary number. All binary numbers must be divisible by 8
The answer is 1 0101 0111 1110 1011 1011 0011 1111 1010 0001 0111
easy, 1011. in binary of course. convert 1011 binary to decimal you get 11.