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What is the circumference and area of a circle with a 17 ft diameter?

The circumference and area of a circle with a 17 ft diameter are:C = 53.4 ftA = 227 ft2


How do you use 227 to find the circumference?

22/7 = Pi. Or 3.14159. With a radius is R*2*Pi With a diameter is 2*Pi


How many square feet in a circle that is 17 feet in diameter?

pi times the square of 8.5 = almost exactly 227 sqft


What the area of a circle that has a diameter of 17?

8.5 x 8.5 x pi 227 sq units within a couple of hundredths.


How many inches are there in 227 yards?

There are 36 inches in one yard. Therefore, 227 yards is equal to 227 x 36 = 8172 inches.


If the diameter of a wheel is 2 feet about how many revolutions does the wheel make for every mile driven Use 227 for pi?

To find the circumference of the wheel, we use the formula C = πd, where d is the diameter. So, the circumference would be C = 227 * 2 = 454 feet. Since there are 5,280 feet in a mile, the wheel would make 5,280 / 454 ≈ 11.63 revolutions for every mile driven.


How many inches is 227 cm?

89.37 inches.


How many inches are there in 227 millimetres?

There are 25.4 millimetres in one inch. Therefore, rounded to two decimal places, 227 millimetres is equal to 227/25.4 = 8.94 inches.


What is 227 inches converted to in feet?

To convert inches to feet just divide by 12 (since there are 12 inches per foot) -227 / 12 = 18.92 feet


What is the area of a 17 foot circle?

The area of a 17-foot circle is: 227 square feet.


What is 227 inches when converted to yards?

6 yds. 11inches


A circular base of a cylinder has a diameter of 14cm its height is 5cm taking pi to be 227 calculate its volume.?

Pi is a constant that is (roughly) equal to 3.14. You cannot arbitrarily take it to be 227! Area of a circle = pi*r2, where r = radius Volume of a cylinder = pi*r2*h, where h = height diameter = 2*r Therefore, r = diameter*1/2 Now, you have all the tools to calculate volume. This must be all illustrated in your textbook. Do your research first, which is called "studying".