16
(3, 2) because x = 3 and y = 2
The two equations represent the same straight line.
x=3
I notice that the ratio of the y-coefficient to the x-coefficient is the same in both equations. I think that's enough to tell me that their graphs are parallel. So they don't intersect, and viewed as a pair of simultaneous equations, they have no solution.
Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.
When x = -2 then y = 4 which is the common point of intersection of the two equations.
If X equals 2, then y = 5
x = -2 and y = 4 (-2,4)
There are two equations in the question, not one. They are the equations of intersected lines, and their point of intersection is their common solution.
x + y = 6x + y = 2These two equations have no common point (solution).If we graph both equations, we'll find that each one is a straight line.The lines are parallel, and have no intersection point.
It is [4m-1, (4m-2)/3]
16
x = 3 and y = 2 so the lines intersect at the point (3, 2)
(3, 2) because x = 3 and y = 2
-6
None. When these two equations are graphed, the two lines are parallel. Since they never intersect, there is no point that satisfies both equations.
The point (4, 5) is.