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The formular is: Number of bytes on a track x Rotation time Therefore, Transfer rate = 1600 x 120 = 192000ms/track

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Q: What is the data transfer rate of an 8 track magnetic tape whose speed is 120 inches per second and density is 1600 bits per inch?
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What is the transfer rate for a nine- track magnetic tape unit whose tape speed is 120 inches per second and whose tape density is 1600 linear bits per inch?

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What is the transfer rate for a nine track magnetic tape unit whose tape speed is 120 inches per second and whose tape density is 1600 linear bits per inch?

1728000bits/


What is the transfer rate of an eight-track magnetic tape whose speed is 120 inches per second and whose density is 1600 bits per second?

-- If you typed the question exactly as you intended to, then the transfer rate is 1,600 bits per second. -- If you actually intended to type "1,600 bits per inch", then the transfer rate is 192,000 bits per second = 24 KBps. -- If the stated density is actually 'per track', then the two figures are 1.6 KBps and 192 KBps.


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