The dent angle of a star polygon is the angle formed by the bent line between two points that form the point angles. I found a PDF that defines the way to calculate that dent angle and checked it out with a know star. It works:
For a star polygon with n points and 2n congruent sides and a point angle of A:
the dent angle B = (360/n) + A
So for an 8 pointed star with a point angle of 20 degrees, the formula says:
(360/8) + 20 = 65 degrees
Note that if the point angle is 135 degrees it is really no longer a star polygon because the two (otherwise bent) line between each of the 8 point becomes 180 degrees. The above formula also proves that Equally for an 8 pointed star polygon formed by joining each second point (forming two over lapped squares, the resultant dent angle becomes 135 degrees. Again the formula confirms that angle. Two home-runs feels pretty good!
The URL reference is:
teach.valdosta.edu/plmoch/MATH3162/Spring%202009/11-3.pdf
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No. In a convex polygon, all the internal angles are smaller than 180 degrees.
the answer is 5 each tip of the star is a acute angle and each angle on the inside of the star is an obtuse angle. there are 5 obtuse angles and no right angles.
A pentagram is a five pointed star. A pentagon in a five sided polygon.
Pentagon
A polygon is a plane figure whose boundary is formed by straight lines. The simplest example is a triangle. A square, rectangle, kite, etc are common 4 sided polygons. Polygons can have angles that are greater than 180 degrees (reflex angles), so a 5 pointed star is a ten sided polygon. There is no limit to the number of sides a polygon can have. If all the sides and angles of a polygon have the same measures, it is called a regular polygon.