circumference or perimeter of the semi-circle = (diameter*pi)/2 + diameter
The area of a circle = (pi)(radius squared); radius = 1/2 the diameter. Therefore, this circle has an area of (pi)(52) = 79 square inches, to the justified number of significant digits.
Area = pi*262 = 676*pi square mm
The formula for the area of a circle is pi (3.141265...) times the radius squared. Since half of the diameter is the radius, plug that number into the formula to get the total square feet.
25 pi sqft A= pi X r2 A= 3.14 X 52 A= 3.14 X 25 A= 78.5 ft.2
The circumference of a circle if the diameter is 52 is 163.4 units.
The circumference of a circle, C, is pi*diameter. If 52 is the diameter, then the equation becomes: C = 3.14159 * 52 or C = 163.36 inches.
circumference of the circle = pi*52 cm
circumference or perimeter of the semi-circle = (diameter*pi)/2 + diameter
The Diameter of a Circle is twice the Radius.thus for a 52 inch Diameter Circle the Radius will be 52/2=26 inches.
From Wolfram Alpha: radius | 26/pi inches8.276 inches diameter | 52/pi inches16.55 inches area | 676/pi in^2 (square inches)215.2 in^2 (square inches)
Circumference = Pi x Diameter, C = 3.14 x 26 = 81.64 inches
Remember the circle eq'n C = pi*d Algebraically rearranging d = C / pi Hence d = 52 pi / pi Cancel down by 'pi' Hence d = 52.
The area of a circle = (pi)(radius squared); radius = 1/2 the diameter. Therefore, this circle has an area of (pi)(52) = 79 square inches, to the justified number of significant digits.
Area = Pi(d/2)2 = Pi*52 = approximately 78.54 inches2
13 m
Area of the circle = pi*radius2 = pi*52