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Q: What is the distance between-1.5 and 2.8?
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Explain how to find the distance between the points (28 -17) and (-15-17) on a coordinate plane?

To find the distance between any two points on the Cartesian plane use Pythagoras: The distance between (x0, y0) and (x1, y1) is given by: distance = √((x1 - x0)² + (y1 - y0)²) → distance between (28, -17) and (-15, -17) is: distance = √((x1 - x0)² + (y1 - y0)²) = √((-15 - 28)² + (-17 - -17)²) = √((-43)² + (0)) = √1849 = 43 ------------------------ In this case, the y-coordinates are the same (y0 = y1 = -17), so this becomes: distance = √((x1 - x0)² + (y0 - y0)²) = √((x1 - x0)² + 0²) = √((x1 - x0)²) = |x1 - x0| The vertical bars around the expression mean the absolute value of the expression, which is the numerical value of the expression ignoring the sign. distance = |x1 - x0| = |-15 - 28| = |-43| = 43.


Explain how to find the distance between the points (28-17) and (-15-17) on a coordinate plane?

the first point is x = 28 and y = -17. The second point is x = -15 and y = -17. Since both points have the same y coordinate then the points are on a straight horizontal line and distance is the difference of the x coordinates, or 28 - (-15) = 43


What is the distance between the points (14 -18) and (-9 -18) in the coordinate plane?

The distance between these two points is 23.


What is the square root of -28?

Go 7 units of distance in any direction. Turn 90 degrees clockwise and go 7 units of distance in a straight line. Turn 90 degrees clockwise and go 7 units of distance in a straight line. Turn 90 degrees clockwise and go 7 units of distance in a straight line.You will have travelled along a square route whose total distance is 28 units. Alternatively you could have turned counter clockwise each time.


How long does it take to drive 28 miles at 45 mph?

1 hour = 60 minutes 1 minute = 60 seconds time = distance/speed = 28 miles/45 mph = 28/45 hour = 28/45 × 60 minutes = 37 1/3 minutes = 37 minutes 1/3 × 60 seconds = 37 minutes 20 seconds

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-3


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-18


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