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Apply Pythagoras

h^(2) = x^(2) + y(2)

Hence for points ( -8,-3 ) & ( 4,5)

h^(2) = (-8-4)^(2) + ( -3-5)^(2).

h^(2) = (-12)^(2) + (-8)^(2)

h^(2) = 144 + 64

h^(2) = 208

h = sqrt(208)

h = 14.222051.... (The distance between the two points.

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lenpollock

Lvl 16
1mo ago

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More answers

If you mean: (-8, -3) and (4, 5) then the distance is 4 times square root 13

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Wiki User

8y ago
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Q: What is the distance between points (-8-3) and (45)?
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