-9
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-13-(-4)=-13+4=-9 but distance is a magnitude so you take the absolute value of the vector -9 and get 9.
Pythagoras can be used to find the distance between any two points (x0, y0) and (x1, y1): Distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((5 - 5)² + (13 - 9)²) = √(0 + 4²) = √(4²) = 4.
Between 3 and 4.
13 and 22
4
sqrt(13) = 3.6... so it lies between 3 and 4.