Pythagoras can be used to find the distance between any two points (x0, y0) and (x1, y1): Distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((5 - 5)² + (13 - 9)²) = √(0 + 4²) = √(4²) = 4.
Between 3 and 4.
13 and 22
If you mean: (-8, -3) and (4, 5) then the distance is 4 times square root 13
4
If you mean: (-8, 4) and (5, 4) Then the distance between the points works out as 13
15
There are 4 prime numbers between 10 and 20. They are 11, 13, 17, and 19.
Pythagoras can be used to find the distance between any two points (x0, y0) and (x1, y1): Distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((5 - 5)² + (13 - 9)²) = √(0 + 4²) = √(4²) = 4.
The even numbers between 1 and 13 are 2, 4, 6, 8, 10, and 12.
Between 3 and 4.
The square root of 13 is approximately 3.6056. The whole numbers that the square root of 13 lies between are 3 and 4. This is because the square of 3 is 9 (less than 13) and the square of 4 is 16 (greater than 13), indicating that the square root of 13 is between 3 and 4.
15
10 (between 7 and 13)
13 and 22
Points: (-4, 5) and (3, 16) Distance: square root of 170 which is about 13
If you mean: (-8, -3) and (4, 5) then the distance is 4 times square root 13