Pythagoras can be used to find the distance between any two points (x0, y0) and (x1, y1): Distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((5 - 5)² + (13 - 9)²) = √(0 + 4²) = √(4²) = 4.
Between 3 and 4.
13 and 22
If you mean: (-8, -3) and (4, 5) then the distance is 4 times square root 13
2 4 6 8 10 12
If you mean: (-8, 4) and (5, 4) Then the distance between the points works out as 13
15
There are 4 prime numbers between 10 and 20. They are 11, 13, 17, and 19.
You can solve this by inspection. Since the square of 3 is less than 13, and the square of 4 is more than 13, it follows that the square root of 13 is between those two numbers.
Pythagoras can be used to find the distance between any two points (x0, y0) and (x1, y1): Distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((5 - 5)² + (13 - 9)²) = √(0 + 4²) = √(4²) = 4.
The even numbers between 1 and 13 are 2, 4, 6, 8, 10, and 12.
Between 3 and 4.
The numbers 5, 7, 11 and 13 are prime.
15
10 (between 7 and 13)
13 and 22
Points: (-4, 5) and (3, 16) Distance: square root of 170 which is about 13