What is the divisibility rule for 27?

Answer 1

Subtract 8 times the last digit from remaining truncated number. Repeat the step as necessary. If the absolute of result is divisible by 27, the original number is also divisible by 27

Check for 945:

94-(8*5)=54;

5-(8*4)=-27

Since 27 is divisible by 27, the original no. 945 is also divisible.

Check for 264681:

26468-(8*1)=26460;

2646-(8*8)=2582;

264-(8*6)=216

21-(8*6)=-27

Since 27 is divisible by 27, the original no. 264681 is also divisible.

Check for 81:

8-(8*1)=0;

Since 0 is divisible by 27, the original no. 81 is also divisible.

Answer 2

To determine if a number is divisible by 27, you must first check if it is divisible by 3 (the sum of its digits is divisible by 3). If the number passes the divisibility test for 3, you then check if it is divisible by 9 (the sum of its digits is divisible by 9). If the number passes both tests, then it is divisible by 27.

Answer 3

Oh, dude, the divisibility rule for 27 is simple! Just add up the digits of the number in question and if the sum is divisible by 27, then the number itself is divisible by 27. Like, if you have the number 81, 8 + 1 = 9, which is divisible by 27, so 81 is divisible by 27. Easy peasy!

Answer 4

Oh honey, buckle up. To check if a number is divisible by 27, you gotta see if it's divisible by 9 first (add up the digits and see if that sum is divisible by 9). If it is, then check if it's divisible by 3. If it passes both tests, then congrats, it's divisible by 27. Math can be a wild ride, but you got this!

Answer 5

That the number is divisible by 9 (digital root = 9) and then that the quotient is divisible by 3 (digital root is a multiple of 3).

The digital root of a number is the sum of all its digits. The digits of the quotient should then be summed and so on.

Answer 6

Its digits add up to 9 and so therefore it is divisible by 9