What is the divisibility rules of 105?

Answer 1

For a number to be divisible by 105 it must be divisible by 3, by 5 and by 7. So, divisibility by 3 requires all three of the following to be satisfied:

1. Sum the digits together. Repeat if necessary. If the answer is 0, 3, 6 or 9 the original number is divisible by 3.
2. If the final digit of the number is 0 or 5, the original number is divisible by 5.
3. Take the number formed by all but the last digit. From it subtract double the last digit. Keep going until there is only one digit left. If it is 0 or 7 then the original number is divisible by 7.

Answer 2

3 5 7