{ [(1+3) *5 ] +7 } /9 = 3 [4 *5] + 7 = 27 divided by 9 = 3 also [ (1+3) / (5+7) ] * 9 = 3 More complex is 13 * (5+7) - 9 = 3 with just signs : -1 -3 +5 -7 + 9 = 3
The domain is the set {-3, -2, 0, 3}. Note that because -2 is mapped to -5 as well as 6, this relationship is not a function.
3+6=9 9-6=3 3+2=5 5+2=7 7-6=1 Heres where it repeats 1+6=7 7-6=1 1+2=3 Answer is 3
9+7+5+3+1 16+5+3+1 21+3+1 24+1 25
3. 1 4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0 2 8 8 4 1 9 7 1 6 9 3 9 9 3 7 5 1 0 5 8 2 0 9 7 4 9 4 4 5 9 2 3 0 7 8 1 6 4 0 6 2 8 6 2 0 8 9 9 8 6 2 8 0 3 4 8 2 5 3 4 2 1 1 7 0 6 7 9 8 2 1 4 8 0 8 6 5 1 3 2 8 2 3 0 6 6 4 7 0 9 3 8 4 4 6 0 9 5 5 0 5 8 2 2 3 1 7 2 5 3 5 9 4 0 8 1 2 8 4 8 1 1 1 7 4 5 0 2 8 4 1 0 2 7 0 1 9 3 8 5 2 1 1 0 5 5 5 9 6 4 4 6 2 2 9 4 8 9 5 4 9 3 0 3 8 1 9 6 4 4 2 8 8 1 0 9 7 5 6 6 5 9 3 3 4 4 6 1 2 8 4 7 5 6 4 8 2 3 3 7 8 6 7 8 3 1 6 5 2 7 1 2 0 1 9 0 9 1 4 5 6 4 8 5 6 6 9 2 3 4 6 0 3 4 8 6 1 0 4 5 4 3 2 6 6 4 8 2 1 3 3 9 3 6 0 7 2 6 0 2 4 9 1 4 1 2 7 3 7 2 4 5 8 7 0 0 6 6 0 6 3 1 5 5 8 8 1 7 4 8 8 1 5 2 0 9 2 0 9 6 2 8 2 9 2 5 4 0 9 1 7 1 5 3 6 4 3 6 7 8 9 2 5 9 0 3 6 0 0 1 1 3 3 0 5 3 0 5 4 8 8 2 0 4 6 6 5 2 1 3 8 4 1 4 6 9 5 1 9 4 1 5 1 1 6 0 9 4 3 3 0 5 7 2 7 0 3 6 5 7 5 9 5 9 1 9 5 3 0 9 2 1 8 6 1 1 7 3 8 1 9 3 2 6 1 1 7 9 3 1 0 5 1 1 8 5 4 8 0 7 4 4 6 2 3 7 9 9 6 2 7 4 9 5 6 7 3 5 1 8 8 5 7 5 2 7 2 4 8 9 1 2 2 7 9 3 8 1 8 3 0 1 1 9 4 9 1 2 9 8 3 3 6 7 3 3 6 2 4 4 0 6 5 6 6 4 3 0 8 6 0 2 1 3 9 4 9 4 6 3 9 5 2 2 4 7 3 7 1 9 0 7 0 2 1 7 9 8 6 0 9 4 3 7 0 2 7 7 0 5 3 9 2 1 7 1 7 6 2 9 3 1 7 6 7 5 2 3 8 4 6 7 4 8 1 8 4 6 7 6 6 9 4 0 5 1 3 2 0 0 0 5 6 8 1 2 7 1 4 5 2 6 3 5 6 0 8 2 7 7 8 5 7 7 1 3 4 2 7 5 7 7 8 9 6 0 9 1 7 3 6 3 7 1 7 8 7 2 1 4 6 8 4 4 0 9 0 1 2 2 4 9 5 3 4 3 0 1 4 6 5 4 9 5 8 5 3 7 1 0 5 0 7 9 2 2 7 9 6 8 9 2 5 8 9 2 3 5 4 2 0 1 9 9 5 6 1 1 2 1 2 9 0 2 1 9 6 0 8 6 4 0 3 4 4 1 8 1 5 9 8 1 3 6 2 9 7 7 4 7 7 1 3 0 9 9 6 0 5 1 8 7 0 7 2 1 1 3 4 9 9 9 9 9 9 8 3 7 2 9 7 8 0 4 9 9 5 1 0 5 9 7 3 1 7 3 2 8 1 6 0 9 6 3 1 8 5 9 5 0 2 4 4 5 9 4 5 5 3 4 6 9 0 8 3 0 2 6 4 2 5 2 2 3 0 8 2 5 3 3 4 4 6 8 5 0 3 5 2 6 1 9 3 1 1 8 8 1 7 1 0 1 0 0 0 3 1 3 7 8 3 8 7 5 2 8 8 6 5 8 7 5 3 3 2 0 8 3 8 1 4 2 0 6 1 7 1 7 7 6 6 9 1 4 7 3 0 3 5 9 8 2 5 3 4 9 0 4 2 8 7 5 5 4 6 8 7 3 1 1 5 9 5 6 2 8 6 3 8 8 2 3 5 3 7 8 7 5 9 3 7 5 1 9 5 7 7 8 1 8 5 7 7 8 0 5 3 2 1 7 1 2 2 6 8 0 6 6 1 3 0 0 1 9 2 7 8 7 6 6 1 1 1 9 5 9 0 9 2 1 6 4 2 0 1 9 8 9
Identify the domain X : -10 , -2 , 0 , 5 , 7 Y : -2 , -1 , 5 , 7 9
Several solutions. 17 + 1 + 1 + 1 + 1 15 + 3 + 1 + 1 + 1 13 + 5 + 1 + 1 + 1, 13 + 3 + 3 + 1 + 1 11 + 7 + 1 + 1 + 1, 11 + 5 + 3 + 1 + 1, 11 + 3 + 3 + 3 + 1 9 + 9 + 1 + 1 + 1, 9 + 7 + 3 + 1 + 1, 9 + 5 + 5 + 1 + 1, 9 + 5 + 3 + 3 + 1 7 + 7 + 5 + 1 + 1, 7 + 7 + 3 + 3 + 1, 7 + 5 + 5 + 3 + 1, 7 + 5 + 3 + 3 + 3 5 + 5 + 5 + 5 + 1 Note that there is only one solution that does not include 1, namely 7 + 5 + 3 + 3 + 3
Domain 1: Social Regard for Learning Domain 2: Learning Environment Domain 3: Diversity of Learners Domain 4: Curriculum Domain 5: Planning, Assessing and Reporting Domain 6: Community Linkages domain 7: Personal Growth and Professional Development
{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}
0.6
{ [(1+3) *5 ] +7 } /9 = 3 [4 *5] + 7 = 27 divided by 9 = 3 also [ (1+3) / (5+7) ] * 9 = 3 More complex is 13 * (5+7) - 9 = 3 with just signs : -1 -3 +5 -7 + 9 = 3
3 = 1 x 3 5 = 1 x 5 7 = 1 x 7 GCF = 1
The domain is the set {-3, -2, 0, 3}. Note that because -2 is mapped to -5 as well as 6, this relationship is not a function.
(1/3)/(7/15) = 1/(7/5) = 5/7
3+6=9 9-6=3 3+2=5 5+2=7 7-6=1 Heres where it repeats 1+6=7 7-6=1 1+2=3 Answer is 3
9+7+5+3+1 16+5+3+1 21+3+1 24+1 25
Example: 1 + 3/5 = ? Step 1: make the denominators the same: 1 = 5/5 Step 2: put the 5/5 into the problem in place of the 1: 1 + 3/5 = 5/5 +3/5 Step 3: add the numerators: 5/5 + 3/5 = 8/5 Example 2: 3 + 6/7 = ? 3 = (3x7)/7 = 21/7 21/7 + 6/7 = 27/7