The solution to this problem is simple if you just work backwards. pH= -log10[H+] You already know what your pH is, so write your equation like this: 4.3= -log10[H+] An understanding of basic logarithm properties lets you know that you can rewrite the equation like this: 10-4.3= [H+] 5.0 *10-5 = [H+]
It is an equation. It could be an algebraic equation, or a trigonometric equation, a differential equation or whatever, but it is still an equation.
Simply that, an "equation".Simply that, an "equation".Simply that, an "equation".Simply that, an "equation".
you don't answer an equation, you solve an equation
The definitive answer is 'pH = -log(10) [H^(+)] In words, ' pH is the negative logarithm, to the base ten, of the hydrogen ion concentration. As an example If H^(+) is 0.002 Then pH = -log(10)[0.002] On the calculator using the 'log' button pH = -(-2.69897...) pH = 2.69897... pH = 2.70 NB This would be an acidic pH NNB pH is always quoted to 2 d.p. only. NNNB Do NOT use the 'ln' button on a calculator.
pH = -log[H+], where [H+] is the hydrogen ion concentration in moles per liter.
How is this different from determining if a value is a solution to an equation?
The pH scale
pH + pOH =14
It is a precise measurement tool for determining how acidic (pH 0) to alkaline (pH 14) a solution of a chemical dissolved in water is.
Because that is how a linear equation is defined!
Ph. W. Zettler-Seidel has written: 'Nomograms for three ramjet performance equations (continuity equation, pressure equation, combustion equation)'
The purpose is to find out how acidic it is
The isoelectric point (pI) is the pH at which a molecule has no net charge. To find pI from the Henderson-Hasselbalch equation, set the net charge of the molecule equal to zero and solve for pH. This equation is derived by considering the acidic and basic dissociation constants of the molecule to calculate the pH at which the net charge is zero.
The pH after mixing two buffers can be calculated using the Henderson-Hasselbalch equation, pH = pKa + log([A-]/[HA]), where [A-] is the concentration of conjugate base and [HA] is the concentration of the weak acid. Given pH of 4 and 6, the pKa can be determined and used in the equation to find the final pH value after mixing.
Its an equation you can use to find the pH of a solution. it is.... --- pH = pKa + log (Base/Acid) --- these may help too Ka = 10^-pKa Kw = Ka*Kb
Equation coefficients show the number of molecules involved in a chemical reaction.