pH = -log[H+]
The solution to this problem is simple if you just work backwards. pH= -log10[H+] You already know what your pH is, so write your equation like this: 4.3= -log10[H+] An understanding of basic logarithm properties lets you know that you can rewrite the equation like this: 10-4.3= [H+] 5.0 *10-5 = [H+]
It is an equation. It could be an algebraic equation, or a trigonometric equation, a differential equation or whatever, but it is still an equation.
Simply that, an "equation".Simply that, an "equation".Simply that, an "equation".Simply that, an "equation".
you don't answer an equation, you solve an equation
pH + pOH =14
pH = -log [H+]
How is this different from determining if a value is a solution to an equation?
The pH scale
pH + pOH =14
our experiment on determining the pH of the ash solution gave us a pH of 11.26
The advantage of using the glass electrode for determining the PH of a solution is because the glass electrode is very sensitive to any change.
It is a precise measurement tool for determining how acidic (pH 0) to alkaline (pH 14) a solution of a chemical dissolved in water is.
Because that is how a linear equation is defined!
Ph. W. Zettler-Seidel has written: 'Nomograms for three ramjet performance equations (continuity equation, pressure equation, combustion equation)'
The purpose is to find out how acidic it is
pH = - log [H+] Rearranging the equation, you get [H+] = 10-pH so if you want to find [H+] when pH equals 3.82, just substitute in the equation. I don't have a calculator as of now, so you'll have to calculate yourself.
1. Why is the phosphate buffer made up by using the Henderson-Hasselbalch equation not the expected pH?