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For a parabola with a y=... directrix, it is of the form:

(x - h)^2 = 4p(y - k)

with vertex (h, k), focus (h, k + p) and directrix y = k - p

With a focus of (3, 6) and a directrix of y = 4, this means:

(h, k + p) = (3, 6) → k + p = 6

y = k - p = 4

→ k = 5, p = 1 (solving the simultaneous equations)

→ vertex is (3, 5)

→ parabola is (x - 3)^2 = 4(y - 5)

which can be rearranged into y = 1/4 x^2 - 3/2 x + 29/4

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Q: What is the equation of the quadratic graph with a focus of (3 6) and a directrix of y 4?
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