54 = 21 x 33
2
The exponent form of 114 is 2^7 * 3^1. This is because 114 can be broken down into its prime factors, which are 2 and 3. There are 7 twos and 1 three in the prime factorization of 114, so the exponent form is 2^7 * 3^1.
6x6x5x6x3x2x3 in exponent form is 2 x 32 x 5 x 63
169 = 132
302 = 21 * 1511
746 = 21 x 3731
54 = 21 x 33
21*31*111 = 66
It is: 21*33*51 = 270
It is: 21*32*51 = 90
594 = 21 x 33 x 111
The prime factorization of 21 is 3 x 7. In exponent form, this would be written as 3^1 x 7^1. This shows that 21 can be expressed as the product of its prime factors, 3 and 7, each raised to the power of 1.
3x3x7 in exponent form is 32 x 7
take your number that will be effected by the exponent, and multiply it by itself how many times the exponent stands for so if you had 122 you would do 12 x 12 so if you had 215 you would do 21 x 21 x 21 x 21 x 21 to get 4084101
2
21 can be written as 2.10 × 101