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2e+0 x 2e+0 x 2e+0 = 8e+0

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what is the exponantial form of (2x2x2)x(2x2x2x2x2)?

To find the exponential form of the expression (2x2x2)x(2x2x2x2x2), we need to simplify the expression first and then express it in exponential form. Given expression: (2x2x2)x(2x2x2x2x2) Simplify the expression: (2x2x2) = 2^3 = 8 (2x2x2x2x2) = 2^5 = 32 Now, substitute the simplified values back into the expression: 8 x 32 = 256 Therefore, the exponential form of (2x2x2)x(2x2x2x2x2) is 256.


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