X=d+32
8z + 5
8 more than twice a number d
2d+8
The algebraic expression for "3 more than a number" can be written as x + 3, where x represents the unknown number. In this expression, the variable x is being increased by 3. This expression can be simplified further if needed, but the basic form is x + 3.
d + 5
The expression is: d+5
(d + 32)
X=d+32
5 × d
8z + 5
In Roman numerals D = 500 so 8 more than D = 508, which in Roman numerals is DVIII.
32+d
8(d-3)
8 more than twice a number d
2d+8
d + 6good luck, And ur welcome:):):):):)