72 / \ 2 36 / \ 6 6 / \ / \ 3 2 3 2
78 6 x 13 (2x3) x 13 The numbers 2, 3, and 13 are prime numbers, so the factor tree is complete. An alternate version of a factor tree for 78 is: 78 2 x 39 2 x (3x13)
12 divided by 2 6,2 6 divided by 2 3,2,2
Factor tree of 40: 40 20,2 10,2,2 5,2,2,2
First, pick a factor pair whose product is 246. Then, for each number that is not prime, choose a factor pair for it. Continue until you have reduced each branch of the tree to prime numbers. Here is a factor tree OS 246, using periods for spacing: ....246 ...../ \ ...6 x 41 ../ \ 2 x 3 The prime factors are 2, 3, and 41.
6 2,3
6 2,3 14 2,7
question:make a factor tree for 36. 6 to the fifth power 6to the fifther power time 6
61 is already prime. It doesn't need a tree.
Just put 6 at the top of your tree and then have 2 and 3 coming off of it.
A factor tree of 78: 78 6 x 13 (2x3) x 13 Since 2, 3, and 13 are prime numbers, the factor tree is complete.
426,72,3,7
78 6 x 13 (2x3) x 13 Since 2, 3, and 13 are prime numbers, the factor tree is complete.
Make a factor-tree and the look for the matches of their prime factorization... Using 6 and 8: 6......... 8 2x3.....4x2 .........2x2 so the prime factorization of 6 is 2x3 and 8 is 2x2x2 so the only match you have is two so the gcf of 6 and 8 is 2
12*6 4*3*2*3
72 / \ 2 36 / \ 6 6 / \ / \ 3 2 3 2
18 6 x 3 (2x3) x 3 Since 2 and 3 are prime numbers, the factor tree is complete. An alternate version of the factor tree for 18 is: 18 2 x 9 2 x (3x3)