Factor tree of 40: 40 20,2 10,2,2 5,2,2,2
Here is a factor tree of eight: 8 / \ 4 2 / \ 2 2
The GCF is 5.
You can simplify the term by approximation! Here is the approach: Let y = √x = x^(½). Then, dy/dx = ½ * x^(-½) = 1/(2√x) Select 115² to be x. Then, we obtain: y = 115 dy/dx = 1/(2 * 115) = 1 / 230 Therefore, we obtain this equation: y - 115 = 1/230 * (x - 115²) If x = 13144, then we have: y - 115 = 1/230 * (13144 - 115²) y = 1/230 * (13144 - 115²) + 115 ≈ 114.65 OR What you can do is to factor out each term by term and extract the perfect square factor out of the √. For instance: √(13144) = √(4 * 3286) = 2√3286
Since 115 ends in five, it will divide by '5'. Hence '5' is one of the factors. 5)115 = 23 Hence '23' is the other factor. Since '23' is a prime number, there are no other factors for 115 , but 5, and 23. except '1' & 115'.
115 5•23. They are both prime, so that's all you have to do :)
345/\3 115/\5 23
115 is the only composite factor of 115.
The factors of 115 are 1, 5, 23, and 115
115 is the only composite factor of 115.
The greatest common factor for {115, 230, 345} is 115. Note that 115 x 2 = 230, and 115 x 3 = 345.
The greatest common factor of 75 and 115 is 5.
The greatest common factor of 115 and 299 is 23.
The greatest common factor of 115 and 224 is 1.
No.
No
The Greatest Common Factor of 75, 115, 150: 5