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Can you find a way to get four fives to equal 17?
(5/5)*(5/5)=1 (5/5)+(5/5)=2 (5+5+5)/5=3 sqrt(5+5)-(5/5)=4 sqrt(5+5)*(5/5)=5 sqrt(5+5)+(5/5)=6 5+((5/5)/5)=7 5+.5+(5*.5)=8 (5+5)-(5/5)=9 sqrt(5+5)+sqrt(5+5)=10 5+5+(5/5)=11 (5*5*.5)-.5=12 (5*5*.5)+.5=13 ((5!/5)*.5)+5=17 (5!/5)*sqrt(5*5)=19 5*5-sqrt(5*5)=20 (55/5)/.5=22 (5!/5)-(5/5)=23 (5!/5)-(5-5)=24 (5!/5)+(5/5)=25 (5*5)+(5/5)=26 (55*.5)-.5=27 (55*.5)+.5=28 (5!/5)+sqrt(5*5)=29 5*5+sqrt(5*5)=30
How do you create equations that equals the numbers 1-10 using five 5's for each?
1 = (5 - 5)*5 + 5/52 = [(5+5)/5]*(5/5)3 = (5+5)/5 + 5/54 = (5+5+5+5)/55 = (5/5)*(5/5)*56 = (5*5)/5 + 5/57 = (5*5 + 5 + 5)/58 = (5+5+5)/5 + 59 = (5*5 - 5)/5 + 510 = (5*5 + 5*5)/5
How many different ways can you make 85 with only 5 10 and 20 bills?
25 different ways: 20, 20, 20, 20, 5 20, 20, 20, 10, 10, 5 20, 20, 20, 10, 5, 5, 5 20, 20, 20, 5, 5, 5, 5, 5 20, 20, 10, 10, 10, 10, 5 20, 20, 10, 10, 10, 5, 5, 5 20, 20, 10, 10, 5, 5, 5, 5, 5 20, 20, 10, 5, 5, 5, 5, 5, 5, 5 20, 20, 5, 5, 5, 5, 5, 5, 5, 5, 5 20, 10, 10, 10, 10, 10, 10, 5 20, 10, 10, 10, 10, 10, 5, 5, 5 20, 10, 10, 10, 10, 5, 5, 5, 5, 5 20, 10, 10, 10, 5, 5, 5, 5, 5, 5, 5 20, 10, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5 20, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 20, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 10, 10, 10, 10, 10, 10, 10, 10, 5 10, 10, 10, 10, 10, 10, 10, 5, 5, 5 10, 10, 10, 10, 10, 10, 5, 5, 5, 5, 5 10, 10, 10, 10, 10, 5, 5, 5, 5, 5, 5, 5 10, 10, 10, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5 10, 10, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 10, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 10, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5
What is the greatest common divisor and least common multiple of 1375 6875 and 78125?
1375=5*5*5*116875=5*5*5*5*1178125=5*5*5*5*5*5*5gcd=5*5*5=1251375=5*5*5*116875=5*5*5*5*1178125=5*5*5*5*5*5*5lcm=5*5*5*5*5*5*5*11=859375
How do you make numbers using 1-5 fives?
6
Fatorial of a number program in javascript?
hi darling
What is the pseudocode of fatorial notation?
First, the answer to what is factorial. Factorial is denoted by '!' N! = N * (N-1) * (N-2) * ... * 3 * 2 * 1. For example, 5! = 5 * 4 * 3 * 2 * 1 = 120. There are two approaches to coding a function that will calculate n!. One does it iteratively, and the other recursively. Iteratively: factorial (n){ result <- 1 for(i <- 1; i <= n; i <- i + 1){ result <- result * i } return result } Recursively: factorial (n){ if n is 1 return 1 return n * factorial(n - 1) } Note that n must be 1 or greater for each of the above methods.
Can you find a way to get four fives to equal 17?
(5/5)*(5/5)=1 (5/5)+(5/5)=2 (5+5+5)/5=3 sqrt(5+5)-(5/5)=4 sqrt(5+5)*(5/5)=5 sqrt(5+5)+(5/5)=6 5+((5/5)/5)=7 5+.5+(5*.5)=8 (5+5)-(5/5)=9 sqrt(5+5)+sqrt(5+5)=10 5+5+(5/5)=11 (5*5*.5)-.5=12 (5*5*.5)+.5=13 ((5!/5)*.5)+5=17 (5!/5)*sqrt(5*5)=19 5*5-sqrt(5*5)=20 (55/5)/.5=22 (5!/5)-(5/5)=23 (5!/5)-(5-5)=24 (5!/5)+(5/5)=25 (5*5)+(5/5)=26 (55*.5)-.5=27 (55*.5)+.5=28 (5!/5)+sqrt(5*5)=29 5*5+sqrt(5*5)=30
How do you create equations that equals the numbers 1-10 using five 5's for each?
1 = (5 - 5)*5 + 5/52 = [(5+5)/5]*(5/5)3 = (5+5)/5 + 5/54 = (5+5+5+5)/55 = (5/5)*(5/5)*56 = (5*5)/5 + 5/57 = (5*5 + 5 + 5)/58 = (5+5+5)/5 + 59 = (5*5 - 5)/5 + 510 = (5*5 + 5*5)/5
How many different ways can you make 85 with only 5 10 and 20 bills?
25 different ways: 20, 20, 20, 20, 5 20, 20, 20, 10, 10, 5 20, 20, 20, 10, 5, 5, 5 20, 20, 20, 5, 5, 5, 5, 5 20, 20, 10, 10, 10, 10, 5 20, 20, 10, 10, 10, 5, 5, 5 20, 20, 10, 10, 5, 5, 5, 5, 5 20, 20, 10, 5, 5, 5, 5, 5, 5, 5 20, 20, 5, 5, 5, 5, 5, 5, 5, 5, 5 20, 10, 10, 10, 10, 10, 10, 5 20, 10, 10, 10, 10, 10, 5, 5, 5 20, 10, 10, 10, 10, 5, 5, 5, 5, 5 20, 10, 10, 10, 5, 5, 5, 5, 5, 5, 5 20, 10, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5 20, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 20, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 10, 10, 10, 10, 10, 10, 10, 10, 5 10, 10, 10, 10, 10, 10, 10, 5, 5, 5 10, 10, 10, 10, 10, 10, 5, 5, 5, 5, 5 10, 10, 10, 10, 10, 5, 5, 5, 5, 5, 5, 5 10, 10, 10, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5 10, 10, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 10, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 10, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5
What is the greatest common divisor and least common multiple of 1375 6875 and 78125?
1375=5*5*5*116875=5*5*5*5*1178125=5*5*5*5*5*5*5gcd=5*5*5=1251375=5*5*5*116875=5*5*5*5*1178125=5*5*5*5*5*5*5lcm=5*5*5*5*5*5*5*11=859375
How do you make numbers using 1-5 fives?
6
What is 1 plus 8 plus 5 plus 4 plus 5 plus 5-5-5-5-5-5-5-5-5-5?
1+8+5+4+5+5-5-5-5-5-5-5-5-5-5 = -17
How many different ways can you change a dollar using only half dollars nickels and quarters?
50 50 25 25 25 25 20 x .05 50 25 25 50 25 5 5 5 5 5 50 5 5 5 5 5 5 5 5 5 5 25 25 25 5 5 5 5 5 25 25 5 5 5 5 5 5 5 5 5 5 25 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5
How do you get numbers by only using four fives?
0: (5x5)-(5x5) 1: (5:5)+5-5 2: (5:5)+(5:5) 3: (5+5+5):5 4: [(5x5)-5]:5 5: [(5-5)x5]+5 6: [(5x5)+5]:5 7: [(5+5):5]+5 10: 5+5+5-5 11: (5:5)+5+5 15: (5x5)-5-5 20: 5+5+5+5 24: (5x5)-(5:5) 25: (5x5)+5-5 26: (5x5)+(5:5) 30: [(5:5)+5]x5 35: (5x5)+5+5 45: [(5+5)x5]-5 50: (5x5)+(5x5) 55: [(5+5)x5]+5 75: (5+5+5)x5 120: (5x5x5)-5 130: (5x5x5)+5 625: 5x5x5x5
5*5*5*5*5*5*5*5*5*5*5*5*5*5*5*5*5*5*5*5*5?
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How do you get 37 using five 5's?
Here is one answer:((5+5)/5 )^5 +5Details:((5+5)/5 )^5 +5= ((10)/5 )^5 +5= 2^5 +5= 32 + 5= 37Another answer:(5*5)+(5!/(5+5))Details:(5*5)+(5!/(5+5))=25 + (5!/10)=25 + (120/10)=25 + 12=37
