Table dimension is 59"x35"x29" please calculate volumetric weight in KG Table dimension is 59"x35"x29" please calculate volumetric weight in KG {| |- | Volumetric WeightVolumetric WeightVolumetric Weight * Volumetric Weight
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volume = width x height x depth
outside of the box
Box of apples = 9 kg + Half the weight of a box of applesThis can be written as...Box of apples = Half the weight of a box of apples + Half the weight of a box of applesThis means that 9 kg = Half the weight of a box of apples, so...9 x 2 = 18 kg
There's no such thing as "area of a box" unless you mean "surface area of a box." Length * width * height gives you the volume of a 3D box. Length * width gives area of a 2D rectangle. Surface area of a box can be found by calculating the area of each face and adding them together.
The formula will depend on what it is that you are trying to find: the volume or the surface area.
As per Indian railways: {(L x B x H) in inches / 1728} X 6 = volumetric weight of one box
volume = width x height x depth
The formula is Length X Width X Height.
V = LWH (Volume = Length x Width x Height)
You would have to contact the manufacturer to be positive, but most builders assume volumetric dimensions. Therefore, the inside dimensions of the box probably total up to 248.891 cubic feet, or perhaps slightly over that.
To calculate the weight of a 100x25 mm mild steel (MS) box section, you need the volume and the density of mild steel. The density of mild steel is approximately 7850 kg/m³. The weight can be calculated using the formula: weight = volume × density. For precise weight, the wall thickness of the box section is also needed; however, a rough estimate for a standard hollow section can be obtained by calculating the volume of the material used.
An example of an inclined plane physics problem is calculating the force required to push a box up a ramp. To solve this problem, you would need to use the formula for calculating the force of gravity acting on the box, as well as the formula for calculating the force required to overcome the incline of the ramp. By applying these formulas and considering the angle of the ramp, you can determine the force needed to push the box up the incline.
v=lwhLength x Width x Height/DepthL x W x H
L x B x D or Length times Bredth times Depth
Assuming it's a regular hexagon, V= 6√3 x2h where x is one of the sides of the hexagonal base and h is the height of the box.
Yes, take all of your extra costs (i.e. shipping, box charges etc.) and divide that number by your total invoice amount.
outside of the box