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Q: What is the formula for the sum of the numbers in the 100th row of Pascals triangle?

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The number of odd numbers in the Nth row of Pascal's triangle is equal to 2^n, where n is the number of 1's in the binary form of the N. In this case, 100 in binary is 1100100, so there are 8 odd numbers in the 100th row of Pascal's triangle.

If you consider row 0 as the row consisting of the single 1, then row 100 has 6 odd numbers.

n = 100 + 7 = 107

How do I get 100th birthday letter

The 100th Fibonacci number is 354,224,848,179,261,915,075.

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Sum of numbers in a nth row can be determined using the formula 2^n. For the 100th row, the sum of numbers is found to be 2^100=1.2676506x10^30.

The number of odd numbers in the Nth row of Pascal's triangle is equal to 2^n, where n is the number of 1's in the binary form of the N. In this case, 100 in binary is 1100100, so there are 8 odd numbers in the 100th row of Pascal's triangle.

The numbers are 100Cn = 100!/[n!*(100-n)!] for n = 0, 1, ... , 100

the answer is 5050

If you consider row 0 as the row consisting of the single 1, then row 100 has 6 odd numbers.

No. As both negative and positive numbers can be odd, there is no first odd number, and therefore no 100th odd number. The 100th odd positive number is 199.

This is the way I would do it: The sum of the 1st & 100th numbers = the sum of the 2nd & 99th numbers = the sum of the 3rd & 98th numbers all the way to the sum of the 50th & 51st numbers; each of the sums equals 200. So I would multiply 200 by 50 (10000).

n = 100 + 7 = 107

The nth triangulat number is n*(n+1)/2 The 100th is 100*101/2 = 5050

100 + 200

100th of 300 hundred is 300th of 100th to the power of 300 times the dividend of 100 and 3, which equals 33 and one third but that's only if the quadratic formula is factorized into vertex and intercept form and then Chuck Norris must verify the answer.

The answer is the 100th triangular number so you can use the formula (n(n+1))/2.n = 100 so the sum is (100 x 101)/2 = 10100/2 = 5,050.

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