The apothem of a regular polygon? well lets look at the math behind it before i recall it... you can scroll down to the bottom of the page if you don't want to read this. the formula is on the bottom of the page * A regular polygon is made up of a sequence of isoceles triangles.. * How do we know that they are isoceles? ------1)the triangles that make up a regular polygon are congruent -------2)the radii are always congruent . the radii of a regular polygon goes from it's center to the vertices...(hint:think of a circle's radius) * due to the fact that you have isoceles triangles they have to be made by angle bisectors through the regular polygon otherwise they couldn't be congruent * okay now that we know that the triangles are isoceles we also know that the apothem is an angle bisector so it cuts the measurement of a side in half. lets use j for our the measurement of our side. * okay we got the angle measures and our apothem made two congruent triangles so now we can use trig ratios to find our apothem so the formula is a=0.5j(tan [n-2]*180/2n) where n is the # of sides and j is the measurement of a side or you can simplify that to a=0.5j(tan [n-2]*90/n) i am using degrees for my angle meausure by the way
The formula for finding an apothem is s = 1/2 aP. S is the area, a is the apothem, and P is the perimeter.
An apothem is a line segment from the center of a regular polygon to the midpoint of a side.
The apothem is 12.5 metres.
102.923cm2 Try using the area of a polygon formula (involves apothem, side length, and number of sides).
That's sort of hard to say. You'd have to use the general area formula, which is, A=1/2(length of apothem)(perimeter of polygon). Yeah, the apothem's the line drawn from the center of the pentagon to the point where it bisects it, you know, like a median. So you'd have to create a right triangle which is 1/2 the length of the side and do 360/5, which is 75. Do 75/2 and then, if you know the side or hypotenuse, use trig to find the apothem and side if needed. Then apply the formula. Okay, so here's an ex. You know the length of the side of a pentagon is 12. So you'd set up the equation sin(75/2)=6/x(your apothem). Simplify that and you get the apothem. Th perimeter'll be 12x5=60 and you'd use the general area formula to solve it. That's about all there is to it. If you still need help, I'd recommend coolmath.com. They might have something on this written in a simple form. I don't know. Try it! Anyhow, hope this works for you!
The formula for finding an apothem is s = 1/2 aP. S is the area, a is the apothem, and P is the perimeter.
The formula is 1/2 (apothem) (perimeter)
The apothem ( a ) of a regular polygon can be found using the formula ( a = \frac{s}{2 \tan(\pi/n)} ), where ( s ) is the length of a side and ( n ) is the number of sides. Alternatively, it can also be calculated using the formula ( a = \frac{A}{P/2} ), where ( A ) is the area of the polygon and ( P ) is the perimeter. The apothem serves as the height of the isosceles triangles formed by connecting the center of the polygon to its vertices.
A = (1/2)Pa A being the area, P being the perimeter of the regular polygon, and the apothem length being a.
To find the apothem length ( a ) of a regular pentagon, you can use the formula for the area ( A ) of a pentagon: [ A = \frac{1}{2} \times Perimeter \times Apothem ] The perimeter ( P ) of the pentagon is ( 5 \times \text{side} = 5 \times 8 = 40 ) in. Given the area ( A = 140 ) sq. in., we can rearrange the formula to find the apothem: [ 140 = \frac{1}{2} \times 40 \times a \implies 140 = 20a \implies a = \frac{140}{20} = 7 \text{ in.} ] Thus, the apothem length is 7 inches.
The formula for finding the area ( A ) of a regular polygon with an apothem ( a ) and the number of sides ( n ) is given by: [ A = \frac{1}{2} \times Perimeter \times Apothem = \frac{1}{2} \times (n \times s) \times a ] where ( s ) is the length of one side. Alternatively, it can also be expressed as: [ A = \frac{1}{2} \times P \times a ] where ( P ) is the perimeter of the polygon.
The apothem ( a ) of an equilateral triangle can be calculated using the formula ( a = \frac{s \sqrt{3}}{6} ), where ( s ) is the length of a side of the triangle. Alternatively, since an equilateral triangle can be divided into two 30-60-90 right triangles, the apothem can also be derived as ( a = \frac{s \sqrt{3}}{2} \div 3 ). This gives you the perpendicular distance from the center to a side of the triangle.
v=lxwxhlenght x width x height its actually Bxh where the base is the apothem x perimeter/2(apothem x peremiter/2)xhhaha pwnedThis is pure bullsh*t
By Apothem LengthThe area of a regular octagon can also be computed using its measured apothem (a line from the center to the middle of any side). The formula for an octagon with side length s and apothem a is Area = a4s . (apothem times one-half the perimeter)So for this example, (8 cm and 9.66 cm) Area = (9.66)(32) = 309.12 cm2----By Side LengthThe area of a regular octagon with side length s is given as Area = 4.828427 s2 , so for a regular octagon of side length 8 cm , the area is calculated as 309.02 cm2. (indicating an error from rounding the apothem length)(This formula is generated by adding or subtracting the missing corner triangles.)
an octagon doesn't have a volume its has and area ecause it is a 2-d figure. to find the area of a 2-d regular figure it is 1/2 apothem * perimeter (apothem is the distance of a line from the center of a polygon, to the midpoint of a side)
If I recall correctly, it is 1/2pa where p is the perimeter and a is the apothem. If I'm wrong, hopefully someone can correct me.
Area of regular polygon: 0.5*apothem*perimeter