What is the greatest 4 digit number which is exactly divisible by 40 48 and 60?

Answer 1

First we need to find the L.C.M. of 40, 48 and 60.

40 = 2x2x2x5

48 = 2x2x2x2x3

60 = 2x2x3x5

After taking out common factors, we have

L.C.M. = 2x2x2x3x5x2 = 240

To find the greatest 4 digit number which is divisible by 240 we divide 9999 by 240.

Remainder = 159

Subtracting this remainder from 9999 we get 9999 - 159 = 9840.

So, the required answer is 9840.

Answer 2

Oh, what a happy little question! To find the greatest 4-digit number divisible by 40, 48, and 60, we need to find the least common multiple (LCM) of these numbers. The LCM of 40, 48, and 60 is 240. So, the greatest 4-digit number divisible by these numbers is 9960 (which is 240 x 41).

Answer 3

Oh, dude, you want the greatest 4-digit number divisible by 40, 48, and 60? That's like asking for the holy grail of numbers. Well, let me drop some knowledge on you - the number you're looking for is 960. It's like the unicorn of numbers, man.

Answer 4

40 = 2x2x2x5

48 = 2x2x2x2x3

60 = 2x2x3x5

After taking out common factors, we have

L.C.M. = 2x2x2x3x5x2 = 240

To find the greatest 4 digit number which is divisible by 240 we divide 9999 by 240.

Remainder = 159

Subtracting this remainder from 9999 we get 9999 - 159 = 9840.

So, the required answer is 9840.