The prime factors of 180a2 are 2, 2, 3, 3, 5, a, and a.
The prime factors of 210a are 2, 3, 5, 7, and a.
The prime factors in common are 2, 3, 5, and a, so the greatest common factor is 2 x 3 x 5 x a = 30a. If a is divisible by 7, there would be two factors of 7 in a2, so the extra 7 would be another factor in common with 210a, in which case the greatest common factor would be 7 x 30a = 210a
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Oh, dude, the greatest common factor of 180a² and 210a is like 30a. You just gotta find the largest number that can divide both of them without leaving a remainder and the highest power of 'a' that appears in both terms. It's like finding the common ground in a messy breakup, just a lot less emotional.